This can only be solved, as far as I know, by trial and error.
The square on the hypoteneuse of a right-angled triangle is equal to the sum of the squares on the two adjacent sides.
The square on the hypoteneuse, in tis case, is 532 = 2809
Trail and error suggests that one of the sides is 28 -(282 = 784) and the other is 45 -(452 = 2025).
Now that we have two adjacent sides we can calculate the area = 28 x 45 = 1260 sq in.
15 and 20 inches because these dimensions comply with Pythagoras' theorem and the area of the rectangle.
A = 168 in2
the width is always shorter than the length. other than that, you would require more information about the rectangle (such as the area or the diagonal measurement) to ascertain the width
The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width
The diagonal multiplied by sin(angle) gives one side of the rectangle and the diagonal times cos(theta) gives the other. So the area is (diagonal)2 x cos(theta) x sin(theta).
15 and 20 inches because these dimensions comply with Pythagoras' theorem and the area of the rectangle.
A = 168 in2
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
If the diagonal is 25m and the area is 168m2 then the longest edge of the rectangle will be 24m.
Lets work it out:- If the legs are 12 and 16 inches, then a rectangle of that size would be 192 square inches in area. As the the diagonal of the rectangle makes two equal triangles (of legs 12 and 16 inches), the area of one of these is half the area of the triangle - 192/2 = 96 square inches.
the width is always shorter than the length. other than that, you would require more information about the rectangle (such as the area or the diagonal measurement) to ascertain the width
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width
The diagonal multiplied by sin(angle) gives one side of the rectangle and the diagonal times cos(theta) gives the other. So the area is (diagonal)2 x cos(theta) x sin(theta).
The diagonal is 14 inches.
It is not possible to answer the question because you have not provided the measurement units for 60 and 120: micrometres, inches, miles?
The area of a rectangle that is 7 inches by 9 inches is 63 inches squared.