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That its roots (solutions) are coincident.
it has one real solution
There are two complex solutions.
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If the discriminant is negative, the roots will be two unreal complex conjugates. If the discriminate is positive the roots will be real.
By calculating the discriminant of the equation and if it's negative the equation will have no solutions
If the discriminant is negaitve, there are no "real" solutions. The solutions are "imaginary".
That its roots (solutions) are coincident.
That its roots (solutions) are coincident.
The discriminant tells you how many solutions there are to an equation The discriminant is b2-4ac For example, two solutions for a equation would mean the discriminant is positive. If it had 1 solution would mean the discriminant is zero If it had no solutions would mean that the discriminant is negative
As stated in the attached link, there are three possible discriminant conditions: Positive, Zero, or Negative. If the discriminant is negative, there are no real solutions but there are two imaginary solutions. So, yes there are solutions if the discriminant is negative. The solutions are imaginary, which is perfectly acceptable as solutions.
It has two complex solutions.
it has one real solution
It has one real solution.
It will then have 2 different roots If the discriminant is zero than it will have have 2 equal roots
No real roots but the roots are a pair of complex conjugates.
There are two complex solutions.