3
Two
2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.
eight
2*2*6 = 24 outcomes.
When you toss a 6-sided die 7 times, each toss has 6 possible outcomes. Since the tosses are independent, you can calculate the total number of outcomes by raising the number of outcomes per toss to the power of the number of tosses: (6^7). This equals 279,936 possible outcomes.
24 or 16
Two
2^4 = 16
2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.
Two times the number of outcomes of the spin - which is not specified in the question.
eight
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
Since there are 2 outcomes for a coin toss, and you will toss the coin 3 times the number of outcomes are 23 or 8. Since H-T-H can occur only 1 way, the probability of the H-T-H sequence is 1/8.
When you toss a coin four times, each toss has 2 possible outcomes: heads or tails. To find the total number of outcomes, you multiply the number of outcomes for each toss together. In this case, it would be 2 x 2 x 2 x 2 = 16 possible outcomes.
when you toss a coin three times, the total number of possible outcomes is
For a coin toss, there are 2 possible outcomes (heads or tails). For five tosses, therefore, there are 25 possible outcomes (25 = 32). However, this assumes that order is important (i.e. that HtttH is different to tHtHt). If you don't care what order the heads or tails fall in, there are only 6 outcomes.
There are 12 possible outcomes.