(CD - ab)^2 = (CD - ab)(CD - ab) = c^2 d^2 - 2abcd + a^2b^2 Try it with say a = 4, b = 3, c = 2 & d = 1: Then CD = 2 and ab = 12 so CD - ab = -10 and squared = 100 c^2 = 4 d^2 = 1 so c^2d^2 = 4 x 1 = 4 a^2 = 16 b^2 = 9 so a^2b^2 = 16 x 9 =144 2abcd = 48 giving 4 - 48 + 144 = 100. Shazam!
== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units
Slope of perpendicular line is the negative reciprocal. So it is -1/4
You need to provide more information in order to answer this question. However, you need to use either Subsitution or Elimination. Substitue the equation of Line AB into the equation of Line CD. E.g. Line AB y=2x Line CD y=3x+2 2x=3x+2 3x-2x=-2 x=-2 Sub x=-2 into either equation y=2(-2) y=-4 Therefore, the point of intersection is (-2, -4).
18
(CD - ab)^2 = (CD - ab)(CD - ab) = c^2 d^2 - 2abcd + a^2b^2 Try it with say a = 4, b = 3, c = 2 & d = 1: Then CD = 2 and ab = 12 so CD - ab = -10 and squared = 100 c^2 = 4 d^2 = 1 so c^2d^2 = 4 x 1 = 4 a^2 = 16 b^2 = 9 so a^2b^2 = 16 x 9 =144 2abcd = 48 giving 4 - 48 + 144 = 100. Shazam!
we can create a graph with the x-axis representing the horizontal values and the y-axis representing the vertical values. let's determine whether the line segments AB and CD are congruent. The length of line segment AB can be calculated using the distance formula: AB = sqrt((x2 - x1)^2 + (y2 - y1)^2) For AB(0, 1) and CD(4, 1), the length of AB is: AB = sqrt((4 - 0)^2 + (1 - 1)^2) = sqrt(16 + 0) = sqrt(16) = 4 For CD(1, 2) and CD(1, 6), the length of CD is: CD = sqrt((1 - 1)^2 + (6 - 2)^2) = sqrt(0 + 16) = sqrt(16) = 4 Since the length of AB is equal to the length of CD (both are 4 units), we can conclude that line segments AB and CD are congruent.
== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units
Slope of perpendicular line is the negative reciprocal. So it is -1/4
You need to provide more information in order to answer this question. However, you need to use either Subsitution or Elimination. Substitue the equation of Line AB into the equation of Line CD. E.g. Line AB y=2x Line CD y=3x+2 2x=3x+2 3x-2x=-2 x=-2 Sub x=-2 into either equation y=2(-2) y=-4 Therefore, the point of intersection is (-2, -4).
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
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A = (2, 1) B = (7, 3) Therefore, AB^2 = (7-2)^2 + (3-1)^2 = 25 + 4 = 29 and so AB = sqrt(29) units.You can find BC, CD, and DA similarly.You will find that AB = BC and CD = DA but that BC is not = CD.Therefore the shape is a kite (two pairs of adjacent sides equal).And perimeter = 2*sqrt(29) + 2*sqrt(50) = 24.9 units.
AB = 2 x 4 (8) C = 3 D = 5
Typically there are 5 types of chemical reactions.(1) synthesis. A + B ==> AB (2) degradation/decomposition. AB ==> A + B (3) combustion. CH4 + 2O2 ==> CO2 + 2H2O (4) single replacement. A + BC ==> AC + B (5) double replacement. AB + CD ==> AD + CB
-1/2 or -0.50
Factors aremultiplicativeterms (i.e., they multiply into all the terms). The easiest way to see this is by example.Example 1:a(b+cd)a is a factor and (b+cd) is a factorExample 2:x2 - 9 = (x-3)(x+3)(x-3) is a factor and (x+3) is a factorHopefully you are beginning to notice you can always wrap parenthesis around a factor without altering the order of operations.Example 3:2a(b)(9n-x)+8This is a trick one, but you can factor out a 2:2a(b)(9n-x)+8 = (1)(2)a(b)(9n-x)+(4)(2) = (2)(ab(9n-x)+4)The factors are: 2 and (ab(9n-x)+4)Example 4:If that +8 wasn't on example 3, what would the factors be?2a(b)(9n-x)They would be:2, a, b, and (9n-x)