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How do you expand cd-ab if the entire expression is in parentheses and squared?
(CD - ab)^2 = (CD - ab)(CD - ab) = c^2 d^2 - 2abcd + a^2b^2 Try it with say a = 4, b = 3, c = 2 & d = 1: Then CD = 2 and ab = 12 so CD - ab = -10 and squared = 100 c^2 = 4 d^2 = 1 so c^2d^2 = 4 x 1 = 4 a^2 = 16 b^2 = 9 so a^2b^2 = 16 x 9 =144 2abcd = 48 giving 4 - 48 + 144 = 100. Shazam!
How do you draw a triangle with an area of 5 square units?
== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units
Slope of a line AB is 4 what is the slope of CD if CD is perpendicular to AB?
Slope of perpendicular line is the negative reciprocal. So it is -1/4
Where does point AB intersects CD?
You need to provide more information in order to answer this question. However, you need to use either Subsitution or Elimination. Substitue the equation of Line AB into the equation of Line CD. E.g. Line AB y=2x Line CD y=3x+2 2x=3x+2 3x-2x=-2 x=-2 Sub x=-2 into either equation y=2(-2) y=-4 Therefore, the point of intersection is (-2, -4).
What is the measure of a secant CD If ab is 14 and bd is 4?
18
