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∙ 15y ago50% will be tall
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∙ 15y agoFrom the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
offspring will be produced in following AA :Aa:aa and is in the ratio of 1:2:1 so the probabiltiy is 50%
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
1/16
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
If the parents are both AA, which results in the cross AA X AA, then the offspring will all be AA. If both parents are AA, resulting in the cross AA X AA, then all offspring will be AA. If BOTH parents are Aa, resulting in the cross Aa X Aa, then the offspring will be 25% AA, 50% Aa, and 25% AA. This is only true if the alleles are not sex-linked.
If ALL offspring are Aa, The parents are AA and aa.
This is due to Mendel's law of segregation, which states that alleles separate during gamete formation and randomly unite during fertilization. Therefore, there is a 25% chance that offspring from an Aa x Aa cross will inherit the genotypes AA, resulting in the expression of the recessive trait.
The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
There are two choices that produce the least phenotypic variation. AA times aa produces only Aa offspring. AA times Aa produces and AA and Aa offspring.
The expected phenotype ratio of seed color in the offspring of an F1 x F1 cross is 3:1. This is because the F1 generation is heterozygous for the trait, resulting in a 3:1 ratio of dominant to recessive phenotypes in the offspring.
A trait determined by a single gene with two alleles will typically have only two possible phenotypes, one associated with each allele. Examples include pea plant seed color (yellow or green) and human blood type (A or B).
No, AA and SS cannot give birth to AA offspring. In this scenario, there would be a 50% chance of producing AS offspring (heterozygous) and a 50% chance of producing SS offspring (homozygous recessive).