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Q: In the cross AA x AA what is the probability of obtaining AA offspring?
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From the cross AA x AA the probability of producing a homozygous dominant offspring is?

From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).


What is the probability of producing a homozygous dominant offspring from the cross of AA and AA?

1/16


From the cross AA X AA the probability of producing a homozygous dominat offspring is?

Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).


The F1 offspring of the monohybrid cross AAA x AAA are?

F1 offspring obtained by monohybrid cross of AA and AA will be Aa.


What alleles would the offspring have if both parents are pure a or pure A?

If the parents are both AA, which results in the cross AA X AA, then the offspring will all be AA. If both parents are AA, resulting in the cross AA X AA, then all offspring will be AA. If BOTH parents are Aa, resulting in the cross Aa X Aa, then the offspring will be 25% AA, 50% Aa, and 25% AA. This is only true if the alleles are not sex-linked.


If all offspring of a cross have the genotype Aa the parents of the crosses would most likely be?

If ALL offspring are Aa, The parents are AA and aa.


When hybrids for a certain characteristic are crossed Aa x Aa the recessive genotype AA may appear in some of the offspring because of what?

This is due to Mendel's law of segregation, which states that alleles separate during gamete formation and randomly unite during fertilization. Therefore, there is a 25% chance that offspring from an Aa x Aa cross will inherit the genotypes AA, resulting in the expression of the recessive trait.


What is the genotypic ratio of the offspring from a cross of AAA x AAA?

The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1


Which cross would produce the least phenotypic variation?

There are two choices that produce the least phenotypic variation. AA times aa produces only Aa offspring. AA times Aa produces and AA and Aa offspring.


What is the expected phenotype ratio of seed color of the offspring of an F1 x F1 cross?

The expected phenotype ratio of seed color in the offspring of an F1 x F1 cross is 3:1. This is because the F1 generation is heterozygous for the trait, resulting in a 3:1 ratio of dominant to recessive phenotypes in the offspring.


What will have only two possible phenotypes?

A trait determined by a single gene with two alleles will typically have only two possible phenotypes, one associated with each allele. Examples include pea plant seed color (yellow or green) and human blood type (A or B).


Can AA and SS give birth to AA?

No, AA and SS cannot give birth to AA offspring. In this scenario, there would be a 50% chance of producing AS offspring (heterozygous) and a 50% chance of producing SS offspring (homozygous recessive).