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From the cross AA x AA the probability of producing a homozygous dominant offspring is?
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
From the cross AA X AA the probability of producing a homozygous dominat offspring is?
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
The F1 offspring of the monohybrid cross AAA x AAA are?
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
What is the genotypic ratio of the offspring from a cross of AAA x AAA?
The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
What is the probability that the genotype AAA will be produced by the parents AAA x AAA?
offspring will be produced in following AA :Aa:aa and is in the ratio of 1:2:1 so the probabiltiy is 50%
From the cross AA x AA the probability of producing a homozygous dominant offspring is?
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
What is the probability of producing a homozygous dominant offspring from the cross of AA and AA?
1/16
From the cross AA X AA the probability of producing a homozygous dominat offspring is?
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
The F1 offspring of the monohybrid cross AAA x AAA are?
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
What alleles would the offspring have if both parents are pure a or pure A?
If the parents are both AA, which results in the cross AA X AA, then the offspring will all be AA. If both parents are AA, resulting in the cross AA X AA, then all offspring will be AA. If BOTH parents are Aa, resulting in the cross Aa X Aa, then the offspring will be 25% AA, 50% Aa, and 25% AA. This is only true if the alleles are not sex-linked.
If all offspring of a cross have the genotype Aa the parents of the crosses would most likely be?
If ALL offspring are Aa, The parents are AA and aa.
When hybrids for a certain characteristic are crossed Aa x Aa the recessive genotype AA may appear in some of the offspring because of what?
This is due to Mendel's law of segregation, which states that alleles separate during gamete formation and randomly unite during fertilization. Therefore, there is a 25% chance that offspring from an Aa x Aa cross will inherit the genotypes AA, resulting in the expression of the recessive trait.
What is the probability of offspring for 2 heterozygous dogs?
The probability of offspring for two heterozygous dogs (Aa x Aa) is 25% homozygous dominant (AA), 50% heterozygous (Aa), and 25% homozygous recessive (aa) based on Mendelian genetics principles.
What is the genotypic ratio of the offspring from a cross of AAA x AAA?
The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
Which cross would produce the least phenotypic variation?
There are two choices that produce the least phenotypic variation. AA times aa produces only Aa offspring. AA times Aa produces and AA and Aa offspring.
If you were to get four different offspring from this cross list the different genotypes and the number of each genotype you would expect?
To provide an accurate answer, I would need the specific parental genotypes involved in the cross. However, if we assume a simple Mendelian cross between two heterozygous parents (e.g., Aa x Aa), the expected genotypes of the offspring would be: AA, Aa, Aa, and aa. This would yield 1 AA, 2 Aa, and 1 aa, resulting in a total of four offspring with the genotypic ratio of 1:2:1.
If the parent genotypes are Aa and Aa is there only two possible genotypes among the offspring?
No, there are more than two possible genotypes among the offspring when both parent genotypes are Aa. The potential genotypes for the offspring are AA, Aa, and aa, resulting in a total of three different genotypes. The expected ratio from a Punnett square for this cross is 1 AA : 2 Aa : 1 aa.
