50% will be tall
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
In a heterozygous cross (e.g., Aa x Aa), the possible genotypes of the offspring are AA, Aa, and aa. The probability of having two offspring with the same genotype can be calculated as follows: the probabilities of each genotype are 1/4 for AA, 1/2 for Aa, and 1/4 for aa. Thus, the probability that both offspring have the same genotype is the sum of the probabilities of each genotype occurring twice: (1/4 * 1/4) + (1/2 * 1/2) + (1/4 * 1/4) = 1/16 + 1/4 + 1/16 = 5/16. Therefore, there is a 5/16 chance that both offspring will have the same genotype.
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
1/16
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
In a heterozygous cross (e.g., Aa x Aa), the possible genotypes of the offspring are AA, Aa, and aa. The probability of having two offspring with the same genotype can be calculated as follows: the probabilities of each genotype are 1/4 for AA, 1/2 for Aa, and 1/4 for aa. Thus, the probability that both offspring have the same genotype is the sum of the probabilities of each genotype occurring twice: (1/4 * 1/4) + (1/2 * 1/2) + (1/4 * 1/4) = 1/16 + 1/4 + 1/16 = 5/16. Therefore, there is a 5/16 chance that both offspring will have the same genotype.
If the parents are both AA, which results in the cross AA X AA, then the offspring will all be AA. If both parents are AA, resulting in the cross AA X AA, then all offspring will be AA. If BOTH parents are Aa, resulting in the cross Aa X Aa, then the offspring will be 25% AA, 50% Aa, and 25% AA. This is only true if the alleles are not sex-linked.
If ALL offspring are Aa, The parents are AA and aa.
This is due to Mendel's law of segregation, which states that alleles separate during gamete formation and randomly unite during fertilization. Therefore, there is a 25% chance that offspring from an Aa x Aa cross will inherit the genotypes AA, resulting in the expression of the recessive trait.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
There are two choices that produce the least phenotypic variation. AA times aa produces only Aa offspring. AA times Aa produces and AA and Aa offspring.