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Is the square root of 1 over 5 a real number and is it rational or irrational?
It is real and irrational.
Is 5 over 1 an irrational number?
Any number that can be represented by a ratio of integers is rational.
What does a rational number times an irrational number equal?
The product of 0 and an irrational is 0 (a rational), the product of a non-zero rational and any irrational is always irrational.
Is the square root of 125 an irrational number?
Yes, the square root of 125 is an irrational number. It can be simplified to ( 5\sqrt{5} ), where ( \sqrt{5} ) is an irrational number. Since the product of a rational number (5) and an irrational number ((\sqrt{5})) is irrational, ( \sqrt{125} ) is also irrational.
Can 0 be an irrational number?
No
Is 6 over 5 a rational number?
Yes since it can be turned or is a fraction.
Is 36 over 5 an irrational number?
no
Is negative 5 over 8 an irrational?
No.
Is -5 over 6 an irrational number?
No
Is 6 over 5 irrational?
No, 6 over 5 is not irrational. Irrational numbers cannot be expressed as a ratio of two integers. In this case, 6 over 5 simplifies to the rational number 1.2, which can be expressed as a ratio of 6 to 5.
Is the square root of 1 over 5 a real number and is it rational or irrational?
It is real and irrational.
Is 2 over 5 rational or irrational?
It is rational
Is 5 over 1 an irrational number?
Any number that can be represented by a ratio of integers is rational.
Is the product of a rational number and an irrational number always irrational?
No. 0 is a rational number and the product of 0 and any irrational number will be 0, a rational. Otherwise, though, the product will always be irrational.
Is the product of a rational number and an irrational number an irrational?
Not necessarily. 0 times any irrational number is 0 - which is rational.
Is the square root of 16 over 5 rational or irrational?
The square root of (any number that isn't a perfect square) is irrational.
Is a rational number times a irrational number?
Can be irrational or rational.1 [rational] * sqrt(2) [irrational] = sqrt(2) [irrational]0 [rational] * sqrt(2) [irrational] = 0 [rational]
