No.
No, 0 over 3 (0/3) is not an irrational number; it simplifies to 0, which is a rational number. Rational numbers can be expressed as the quotient of two integers, and since 0 can be represented as 0/1 or 0/3, it fits the definition of a rational number.
It is real and irrational.
Any number that can be represented by a ratio of integers is rational.
The product of 0 and an irrational is 0 (a rational), the product of a non-zero rational and any irrational is always irrational.
Yes, the square root of 125 is an irrational number. It can be simplified to ( 5\sqrt{5} ), where ( \sqrt{5} ) is an irrational number. Since the product of a rational number (5) and an irrational number ((\sqrt{5})) is irrational, ( \sqrt{125} ) is also irrational.
Yes since it can be turned or is a fraction.
no
No
No.
No, 6 over 5 is not irrational. Irrational numbers cannot be expressed as a ratio of two integers. In this case, 6 over 5 simplifies to the rational number 1.2, which can be expressed as a ratio of 6 to 5.
It is real and irrational.
It is rational
Any number that can be represented by a ratio of integers is rational.
No. 0 is a rational number and the product of 0 and any irrational number will be 0, a rational. Otherwise, though, the product will always be irrational.
Not necessarily. 0 times any irrational number is 0 - which is rational.
The square root of (any number that isn't a perfect square) is irrational.
Can be irrational or rational.1 [rational] * sqrt(2) [irrational] = sqrt(2) [irrational]0 [rational] * sqrt(2) [irrational] = 0 [rational]