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What is the only number whose value is twice the sum of its digits?
18
How many two-digit numbers are twice the sum of their digits?
Only one . . . . . 18
The sum of the digits of the number is 6?
the sum of my digits is 6? answer=60
What is the only number that is equal to twice the sum of it's digits?
Well 18 works. [1+8 = 9]. It's not exactly the only one, though. Consider zero. The sum of the digits (0) is zero. And twice zero = zero.Here are some ideas to see if there are others: For 1-digit numbers, the number is the sum, so the zero, above, is the only one that satisfies the conditions. For 2-digit numbers, the largest sum possible is 18 [99: 9 + 9]. Twice that sum is 36, so no numbers greater than 36 (with 2-digit numbers).Now consider the unknown number with digits AB. So the sum = A + B, and the number = 10*A + B. Now the number is twice the sum, so:10*A + B = 2*(A + B). Rearranging, we have 8*A = B, so you can substitute whole numbers for A, and calculate B. There is the trivial case of zero: 8*0 = 0, which was already covered. If A = 1, then B = 8, which gives us 18. With A = 2, then B= 16, so that's not a 2-digit number. So 18 is the only 2-digit number.What about 3-digits: the largest 3-digit sum is 9+9+9=27. Twice that is 54, which is a 2-digit number. So there can be no 3-digit numbers, satisfying the conditions.
How do you find the sum of digits of each number?
Add the digits together. The sum of the digits of 23 is 5.
What is the only number whose value is twice the sum of its digits?
18
What two digit number is twice the sum of its digits?
18 is the only number that matches these criteria.
What are some What are facts about the number 18?
18 is the only number (other than 0) that is twice the sum of its digits.
What number is twice the sum of its digits?
18. 1+8=9 9x2=18
How many two-digit numbers are twice the sum of their digits?
Only one . . . . . 18
The sum of the digits of the number is 6?
the sum of my digits is 6? answer=60
What is the only number that is equal to twice the sum of it's digits?
Well 18 works. [1+8 = 9]. It's not exactly the only one, though. Consider zero. The sum of the digits (0) is zero. And twice zero = zero.Here are some ideas to see if there are others: For 1-digit numbers, the number is the sum, so the zero, above, is the only one that satisfies the conditions. For 2-digit numbers, the largest sum possible is 18 [99: 9 + 9]. Twice that sum is 36, so no numbers greater than 36 (with 2-digit numbers).Now consider the unknown number with digits AB. So the sum = A + B, and the number = 10*A + B. Now the number is twice the sum, so:10*A + B = 2*(A + B). Rearranging, we have 8*A = B, so you can substitute whole numbers for A, and calculate B. There is the trivial case of zero: 8*0 = 0, which was already covered. If A = 1, then B = 8, which gives us 18. With A = 2, then B= 16, so that's not a 2-digit number. So 18 is the only 2-digit number.What about 3-digits: the largest 3-digit sum is 9+9+9=27. Twice that is 54, which is a 2-digit number. So there can be no 3-digit numbers, satisfying the conditions.
The units digit of a two digit number exceeds twice the tens digit by 1 what numbers if the sum of its digit is 10?
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
How do you find the sum of digits of each number?
Add the digits together. The sum of the digits of 23 is 5.
Below 40 a prime number the sum of its digits is 11?
what number is prime to 40 29 - it's a prime number (divisible only by 1 and itself) and if you sum the two digits 2 + 9 = 11
What is a 2-digit number the sum of whose digits is 1?
1
How many one-digit numbers are twice the size the sum of their digits?
None. The sum of one digit can't be twice the size of the digit.
