There is no such pair. The solution to equation 1 and equation 2 is x = 1, y = 1. The solution to equation 2 and equation 3 is x = 1, y = 1. And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions. The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
10 (-2) 5 (-4)
-2
Without an equality sign it is not an equation but if you mean: 5x=2 then x=2/5 or 0.4
2x -5 = 2-12x -5 +5= 2-1+52x = 62x/2 = 6/2x = 3
There is no such pair. The solution to equation 1 and equation 2 is x = 1, y = 1. The solution to equation 2 and equation 3 is x = 1, y = 1. And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions. The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.
Presumably this is a quadratic equation question asking you to find the solution of 2x2+9x-5 = 0 First factorise the expression in the equation in order to find its solution. (2x-1)(x+5) = 0 Solution: x = 1/2 or x = -5
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
2 is a solution of the equation, but not if it's an inequality.
It is [1 + sqrt(5)]/2 It is the solution to the equation 1/x = x/(1+x)
The solution set of the equation x - 5 - 2 is x = 7. Therefore, the solution set is {7}.
10 (-2) 5 (-4)
-2
I understand the equation to be y = -3x - 2 and the point to be (5,1). I substitute 1 for each appearance of y and 5 for each appearance of x: 1 = -3(5) - 2 = -15 - 2 = -17, which is not a true statement. Therefore, that is not a solution. To get a solution, set x=1, and calculate y by substituting this value (1) for x wherever it appears: y = -3(1) - 2 = -3 - 2 = -5. Therefore, (-5,1) is a solution. (I suspect that this is what you meant to put in the question.)
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
Without an equality sign it is not an equation but if you mean: 5x=2 then x=2/5 or 0.4