its odd. take a look at my example below.
each O has a partner, the way i arranged it. but if i take all but one away, the O doesnt have a partner, so the number one is odd.to tell if other numbers are odd, just ask if you can group that many people into pairs without someone alone or with a group of three
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The number 1 is an odd number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
*1 is an odd number * 0 is an even number
odd
because... odd+odd=even even+odd=odd e.g 1+1+1=3 odd+odd+odd=odd
No. The sum of 1 odd number and 1 even number must always be odd.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
The number 1 is an odd number.
odd
An odd number plus an odd number will be an even number. Odd number A is (even number + 1) Odd number B is (even number + 1) A + B = (even number + 1) + (even number + 1) = even number + even number + 2 Since all even numbers are divisible by 2 and 2 is divisible by 2, each part of the result is divisible by 2, so the sum as a whole is divisible by 2, which means it is an even number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
*1 is an odd number * 0 is an even number
Answer:1 is an odd number If you need to learn math go to the web site in the link below
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times even is even.
odd
because... odd+odd=even even+odd=odd e.g 1+1+1=3 odd+odd+odd=odd
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Even plus odd is odd.