As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
It is divisible by 10, but not by 235.
If you mean: 2, 3 and 5 then they are 71, 73, 77 and 79
235 is a composite number because it has more than two divisors - contrary to a prime which has exactly two divisors: 1 and the prime itself. 235 has 4 divisors: 1, 5, 47 and 235. A quick way to determine this is done by looking at the last digit. If it is either 0 or 5 the number is divisible by 5, thus it is not a prime.
The number is bigger than 5 but ends in 5 so it is divisible by 5. Therefore it cannot be a prime.
As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
It is divisible by 10, but not by 235.
To determine if 90005 is divisible by a specific number, we need to check if the number divides evenly into 90005 without leaving a remainder. For example, to check if 90005 is divisible by 5, we would divide 90005 by 5. If the result is a whole number without a remainder, then 90005 is divisible by 5. Similarly, this process can be applied to other numbers such as 2, 3, 4, 6, 9, 10, and so on.
235 is not divisible by three. The factors of 235 are 1, 5, 47, 235.In long division, 235 divided by 3 equals 78 with a remainder of 1.
235 and its multiples.
If you mean: 2, 3 and 5 then they are 71, 73, 77 and 79
No.
No.
No.
No. 4,355 is only divisible by these numbers: 1 5 13 65 67 335 871 and 4355.
235 is a composite number because it has more than two divisors - contrary to a prime which has exactly two divisors: 1 and the prime itself. 235 has 4 divisors: 1, 5, 47 and 235. A quick way to determine this is done by looking at the last digit. If it is either 0 or 5 the number is divisible by 5, thus it is not a prime.
The number is bigger than 5 but ends in 5 so it is divisible by 5. Therefore it cannot be a prime.