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To check for divisibility by 9 add the digits of the number and if the sum is divisible by 9 then the original number is also divisible by 9, otherwise it is not.
For 24815: 2 + 4 + 8 + 1 + 5 = 20 which is not divisible by 9, so 24815 is not divisible by 9.
Note that the test can be applied to the sum: repeatedly summing the digits of the sum of the digits until a single digit remains means the original number is divisible by 9 only if this single digit is 9, otherwise it is not (instead it gives you the remainder when the original number is divided by 9). This single digit is known as the digital root of the number.
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Is 24815 divisible by both 9 and 6?
Of course 24815 is divisible by both numbers. Any real number can be divided by any real number except 0. In both cases above, you will get infinitely repeating remainders.
What numbers is divisible by both 9 and 4 A 24815 B 18324 C 9140 D 9126?
To determine which number is divisible by both 9 and 4, we need to check if the number is divisible by both 9 and 4 simultaneously. A number is divisible by 9 if the sum of its digits is divisible by 9. A number is divisible by 4 if the number formed by its last two digits is divisible by 4. Among the options provided, only option D, 9126, meets both criteria as the sum of its digits is 18 (divisible by 9) and the number formed by its last two digits is 26 (divisible by 4).
Is 1110 divisible by 9?
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
Is 127 divisible by 9?
No it is not divisible by 9 .
Are all numbers divisible by 3 also by 9 give example?
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
