No. To check for divisibility by 9 add the digits of the number and if the sum is divisible by 9 then the original number is also divisible by 9, otherwise it is not. For 24815: 2 + 4 + 8 + 1 + 5 = 20 which is not divisible by 9, so 24815 is not divisible by 9. Note that the test can be applied to the sum: repeatedly summing the digits of the sum of the digits until a single digit remains means the original number is divisible by 9 only if this single digit is 9, otherwise it is not (instead it gives you the remainder when the original number is divided by 9). This single digit is known as the digital root of the number.
Both. 18 / 6 = 3 and 18 / 9 = 2
If your stuck go for the lowest common multiple, multiply 6x9 and then you have a number that is divisible by both. (54)
To determine which number is divisible by 3, 6, and 9, we need to check if the sum of the digits of each number is divisible by 3. For 369: 3+6+9 = 18, which is divisible by 3, 6, and 9. Therefore, 369 is divisible by 3, 6, and 9. For 246: 2+4+6 = 12, which is divisible by 3 but not by 6 or 9. Therefore, 246 is divisible by 3 but not by 6 or 9. For 468: 4+6+8 = 18, which is divisible by 3, 6, and 9. Therefore, 468 is divisible by 3, 6, and 9. For 429: 4+2+9 = 15, which is divisible by 3 but not by 6 or 9. Therefore, 429 is divisible by 3 but not by 6 or 9. Therefore, the numbers 369 and 468 are divisible by 3, 6, and 9.
99990
No. To check for divisibility by 9 add the digits of the number and if the sum is divisible by 9 then the original number is also divisible by 9, otherwise it is not. For 24815: 2 + 4 + 8 + 1 + 5 = 20 which is not divisible by 9, so 24815 is not divisible by 9. Note that the test can be applied to the sum: repeatedly summing the digits of the sum of the digits until a single digit remains means the original number is divisible by 9 only if this single digit is 9, otherwise it is not (instead it gives you the remainder when the original number is divided by 9). This single digit is known as the digital root of the number.
B
Every number is divisible by any non-zero number. 1485 is not evenly divisible by both of them.
Both. 18 / 6 = 3 and 18 / 9 = 2
Yes to both.
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.
Every number is divisible by any non-zero number. Furthermore, 405 is evenly divisible by both 3 and 9.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
If your stuck go for the lowest common multiple, multiply 6x9 and then you have a number that is divisible by both. (54)
54
54.
How about: 108