How about 27
405 is divisible by: 1, 3, 5, 9, 15, 27, 45, 81, 135, 405.
27 is divisible by 1, 3, 9, 27.
No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
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No.
How about 27
405 is divisible by: 1, 3, 5, 9, 15, 27, 45, 81, 135, 405.
27 is divisible by 1, 3, 9, 27.
No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
27 is wholly divisible by 1, 3, 9, and 27.
The number 350 is even, so it's divisible by 2; 350/2 = 175. 175 ends with a 5, so it's divisible by 5; 175/5 = 35. The same applies to 35; 35/5 = 7. Our factors are now 2 X 5 X 5 X 7, which are all prime numbers. Therefore, that's the prime factorization of 350: 2 X 52 X 7.
No.
No.
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1 (350/1=350) 2 (350/2=175) 5 (350/5=70) 7 (350/7=50) 10 (350/10=35) 14 (350/14=25) 25 (350/25=14) 35 (350/35=10) 50 (350/7=50) 70 (350/70=5) 175 (350/175=2) 350 (350/350=1)
yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.