No.
27350 is divisible by 5. If you mean 27 and 350, the former is not divisible by 5 but the latter is.
How about 27
405 is divisible by: 1, 3, 5, 9, 15, 27, 45, 81, 135, 405.
27 is divisible by 1, 3, 9, 27.
No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
27 is wholly divisible by 1, 3, 9, and 27.
Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27 Check for 945: 94-(8*5)=54; 5-(8*4)=-27 Since 27 is divisible by 27, the original no. 945 is also divisible. Check for 264681: 26468-(8*1)=26460; 2646-(8*8)=2582; 264-(8*6)=216 21-(8*6)=-27 Since 27 is divisible by 27, the original no. 264681 is also divisible. Check for 81: 8-(8*1)=0; Since 0 is divisible by 27, the original no. 81 is also divisible.
yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.
The prime factors of 675 are 3, 3, 3, 5, and 5, so 675 is divisible by 3 and 5. It is also divisible by the product of any two or more of those factors so, for instance, 675 is divisible by 9, 15, 25, 27, 75, etc.
It's divisible by 3, 5, 9, and 27
There are 27 such numbers.
12, 27, 31. 1,2,3,4,6,7,8,9,11,12,13,14,16. The list goes on and on! If a number is divisible by five that means that you can divide the number by five and get a whole number. For example, you can divide 20 by 5 (20/5) and get 4. Therefore 20 is divisible by five. anything that does not end in 5 or 0 will not be divisible by 5