The square root of 2 is irrational. In general, the square root of a positive integer is either an integer (if you take the square root of a perfect square), or it is irrational.
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.
Obviously not. The square root of 1 is 1. The square root of 4 is 2. So the square roots of 2 and 3 are somewhere between 1 and 2. Just try entering root 2 in your calculator and try not to ask stupid questions.
Yes it is.Since the square of an integer is called a perfect square, then the square root of a perfect square must be an integer.
The square root of 4 is 2 (and -2) and is an integer.
Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.
The square root of 2 is irrational. In general, the square root of a positive integer is either an integer (if you take the square root of a perfect square), or it is irrational.
The square root of an integer is a CYCLOTOMIC integer.
No. by definition, the polynomial should contain an integer as exponent and square root 1/2 is not an integer.
No. The square root of 2 is approximately 1.414. Since there are non-zero digits after the decimal point, that means it is NOT an integer.
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
The square root of 3 is not an integer.
Is the square root of a 100 is a integer
no.No. The square root of 5 is an irrational number. The two closest numbers with integer square roots are 4 (with a square root of 2) and 9 (with a square root of 3). Since there are no integers between 2 and 3 and 5 lies between 4 and 9, it's pretty evident that it can't have an integer square root.
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106