It is an expression that can be simplified to: 3-21n
n = 7. 3(7) + 7 = 28. 21+7=28
3n2-8n+4 = (3n-2)(n-2) when factored
3(3n - 1)(n + 1)
It's kind of tough to look for the 'answer', because it's not even clear what the question is.All I can think of is: Somebody tells you what 'n' is, and then you're supposed tofigure out what number 5('n' squared + 3n) is. If that's the question, then of courseyou need to know what 'n' is before you can start on it.I'm, not at all sure that that's the question, but it's all I can think of, so here's an example:Let's say that 'n' is 1 .n2 = 13n = 3n2 + 3n = 45('n' squared + 3n) = 54 = 625That may not be too helpful, because, as I said above, the way you postedthe question, I can't see what the 'problem' (the assignment) is.
It is an expression that can be simplified to: 3-21n
3n + 3(6 + 7n) = 3n + 18 + 21n = 24n + 18
n = 7. 3(7) + 7 = 28. 21+7=28
3n2-8n+4 = (3n-2)(n-2) when factored
(3n)2 = 9n2
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
3(3n - 1)(n + 1)
3n+2+3n+2=6n+4
The GCF is 3n.
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
No. 3n is not a factor of 3n + 7.
6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.