Yes. First you need to factor out a 3 so the equation becomes 3(n2-8n+12). Then you need to factor what's in the parenthesis, which would be (n-6)(n-2). So, the answer is 3(n-6)(n-2).
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It is an expression that can be simplified to: 3-21n
n = 7. 3(7) + 7 = 28. 21+7=28
3n2-8n+4 = (3n-2)(n-2) when factored
3(3n - 1)(n + 1)
It's kind of tough to look for the 'answer', because it's not even clear what the question is.All I can think of is: Somebody tells you what 'n' is, and then you're supposed tofigure out what number 5('n' squared + 3n) is. If that's the question, then of courseyou need to know what 'n' is before you can start on it.I'm, not at all sure that that's the question, but it's all I can think of, so here's an example:Let's say that 'n' is 1 .n2 = 13n = 3n2 + 3n = 45('n' squared + 3n) = 54 = 625That may not be too helpful, because, as I said above, the way you postedthe question, I can't see what the 'problem' (the assignment) is.