No it is not.
Wiki User
∙ 12y agoit is divisible by 3 which is 141
NO
Yes.
Any of its factors including itself
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
Yes, it is a composite number. It's divisible by 3. A quick way to tell if a number is divisible by 3 is to add up all the digits in the number. If their sum is divisible by 3, then the number is divisible by 3. For example, 4 + 2 + 3 = 9, and 9 is obviously divisible by 3. So, 423 must be divisible by 3. 423 divided by 3 is 141.
it is divisible by 3 which is 141
NO
Yes. 423 is divisible by 1, 3, 9, 47, 141, 423.
Yes.
Any of its factors including itself
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
423 divided by 86 equals 4 with a remainder of 79.
4 is not divisible by 684. 684 is divisible by 4.
Is 348 divisible by 4?
No. If the last two digits of a number are divisible by 4, then the whole number is divisible by 4. So, 34 is not divisible by 4, therefore 634 is not divisible by 4.