No it is not.
it is divisible by 3 which is 141
NO
Yes.
Any of its factors including itself
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
it is divisible by 3 which is 141
Yes, it is a composite number. It's divisible by 3. A quick way to tell if a number is divisible by 3 is to add up all the digits in the number. If their sum is divisible by 3, then the number is divisible by 3. For example, 4 + 2 + 3 = 9, and 9 is obviously divisible by 3. So, 423 must be divisible by 3. 423 divided by 3 is 141.
NO
Yes. 423 is divisible by 1, 3, 9, 47, 141, 423.
Yes.
Any of its factors including itself
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
4 is not divisible by 684. 684 is divisible by 4.
Yes 1124 is divisible by 4. Since 24 is divisible by 4 1124 is divisible by 4. If the last two numbers of a number are divisible by 4, the number is divisible by 4. 24 divided by 4 is 6.
A number is divisible by 4 if the last two digits form a number that is divisible by 4, for example 612 is divisible by 4 (because 12 is divisible by 4).
10230000648 is evenly divisible by 4. If the last two digits of an integer are divisible by 4, the entire number is divisible by four.