it is divisible by 3 which is 141
Yes, it is a composite number. It's divisible by 3. A quick way to tell if a number is divisible by 3 is to add up all the digits in the number. If their sum is divisible by 3, then the number is divisible by 3. For example, 4 + 2 + 3 = 9, and 9 is obviously divisible by 3. So, 423 must be divisible by 3. 423 divided by 3 is 141.
Yes. 423 is divisible by 1, 3, 9, 47, 141, 423.
No it is not.
NO
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
Any of its factors including itself
423 141,3 47,3,3 3 x 3 x 47 = 423
423/3 = 141
The prime factors of 423 are: 3 x 3 x 47
423 = 3 * 3 * 47 = 3^2 * 47.
423 = 1*423, 3*141, 9*47