it is divisible by 3 which is 141
Yes, it is a composite number. It's divisible by 3. A quick way to tell if a number is divisible by 3 is to add up all the digits in the number. If their sum is divisible by 3, then the number is divisible by 3. For example, 4 + 2 + 3 = 9, and 9 is obviously divisible by 3. So, 423 must be divisible by 3. 423 divided by 3 is 141.
No it is not.
Yes. 423 is divisible by 1, 3, 9, 47, 141, 423.
Yes.
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
Any of its factors including itself
211.5
Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.
4,230 is divisible by 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 47, 90, 94, 141, 235, 282, 423, 470, 705, 846, 1410, 2115, 4230.
4230 is divisible by 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 47, 90, 94, 141, 235, 282, 423, 470, 705, 846, 1410, 2115, 4230
423 = 3 * 3 * 47 = 3^2 * 47.