Q: Is 477 divisible by 3 6 and 9?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

of course its divisable by all 3... if you divide by 3 or 9 you get a whole number answer if thats what you meant

Add together the digits of the number to be divided by 3. If the sum is 3 or a multiple of 3 then the number is divisible by 3. Example : 5681 ; 5 + 6 + 8 + 1 = 20 which is not a multiple of 3 so 5681 is NOT divisible by 3. 477 ; 4 + 7 + 7 = 18 which is a multiple of 3 so 477 is divisible by 3. NOTE : When adding the digits, the digits of the total can be summed to determine if the original number is divisible by 3. In the example 4 + 7 + 7 = 18 then 1 + 8 = 9, and 9 is a multiple of 3 so confirming that 477 is divisible by 3.

72,344 is not evenly divisible by 3 or by 6 or by 9.

42 is divisible by 2, 3 and 6 but not by 9.

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.

Related questions

of course its divisable by all 3... if you divide by 3 or 9 you get a whole number answer if thats what you meant

954 is divisible by: 1 2 3 6 9 18 53 106 159 318 477 954.

add up all the individual digits in the number. if the answer has more than one digit, add the digits of the answer up. keep doing this till you get a single number. if the answer is 3, 6 or 9 the number is divisible by 3. eg 477 4 + 7 + 7 = 18 1 + 8 = 9 answer is 9, so 477 is divisible by 3

1, 2, 3, 6, 9, 18, 53, 106, 159, 318, 477, 954.

Add together the digits of the number to be divided by 3. If the sum is 3 or a multiple of 3 then the number is divisible by 3. Example : 5681 ; 5 + 6 + 8 + 1 = 20 which is not a multiple of 3 so 5681 is NOT divisible by 3. 477 ; 4 + 7 + 7 = 18 which is a multiple of 3 so 477 is divisible by 3. NOTE : When adding the digits, the digits of the total can be summed to determine if the original number is divisible by 3. In the example 4 + 7 + 7 = 18 then 1 + 8 = 9, and 9 is a multiple of 3 so confirming that 477 is divisible by 3.

Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.

No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6

72,344 is not evenly divisible by 3 or by 6 or by 9.

1350 is divisible by all of the numbers of 3, 6 and 9

42 is divisible by 2, 3 and 6 but not by 9.

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.