Yes, no, yes.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
It is divisible by 2, 5 and 10, but not 3 and 9.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
To determine if 1485 is divisible by 2, 3, 5, 6, 9, and 10, we can check each divisor. 1485 is odd, so it is not divisible by 2. It is divisible by 3 (since the sum of its digits, 1+4+8+5=18, is divisible by 3) and by 5 (it ends in 5). However, since it is not divisible by 2, it cannot be divisible by 6 or 10, and since it is not divisible by 9 (the sum of its digits is not divisible by 9), it is not divisible by that either. Thus, 1485 is only divisible by 3 and 5.
Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10