5,890 is divisible by: 1, 2, 5, 10, 19, 31, 38, 62, 95, 155, 190, 310, 589, 1178, 2945 and 5890.
Any number ending is zero is divisible by 2. 5890 / 2 = 2945
Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.
No.
The trick to determining whether a number is divisible by 9 is to add all the individual numbers of the large number together and see if the result is divisible by 9. Let's add 5 + 8 + 9 + 0 = 22. Since 22 is not neatly divisible by 9, then we know that the larger 5890 is also not divisible by 9. Of course, you can divide it by 9, but there will be something left over.
Yes, both.
yes!
5,890 is divisible by: 1, 2, 5, 10, 19, 31, 38, 62, 95, 155, 190, 310, 589, 1178, 2945, 5890.
5,890 is divisible by: 1, 2, 5, 10, 19, 31, 38, 62, 95, 155, 190, 310, 589, 1178, 2945 and 5890.
5890 ÷ 3 = 1963.33 recurring.
Any number ending is zero is divisible by 2. 5890 / 2 = 2945
is not
Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.
yes the answer is 1472.5
Yes; 1178.
No, none of them.
No.