No, 98 is an even number so it is divisible by 2.
No, 98 is divisible by 2; therefore, it is a composite number.
98 is the largest two digit number divisible by 7.
No, but 98 is divisible by 298/2 = 49
Numbers that are divisible by 49 are those that can be expressed as 49 times an integer. This includes positive and negative multiples of 49, such as 49, 98, 147, -49, -98, and so on. In general, any number in the form of (49n), where (n) is an integer, is divisible by 49.
No. Any number that ends with 0, 2, 4, 6, 8 is an even number; all even numbers are divisible by 2; so none of them (except for 2 itself) can be a prime number.
No, 98 is an even number so it is divisible by 2.
yes
108 is divisible by 3.
No, 98 is divisible by 2; therefore, it is a composite number.
No. To check for divisibility by 9 add the digits together and if this sum is divisible by 9 then so is the original number. This can be repeated until a single digit remains which must be 9 for the original number to be divisible by 9. For 98: 9 + 8 = 17 → 1 + 7 = 8 which is not 9, so 98 is not divisible by 9.
98 is divisible by two, 99 is not, so 98.
98 is the largest two digit number divisible by 7.
No, but 98 is divisible by 298/2 = 49
No, it isn't. You can always check - by adding the digits together. If the resulting number is divisible by 3, then the original number is too. In this example - 9+8=17... 17 will NOT divide by three exactly therefore 98 won't either.
Since it ends with an 8, it's an even number, which means it's divisible by 2. That's all we need, in order to know that it can't be a prime number, so it must be composite. Put that little factoid in your pocket and keep it: No even number except 2 is a prime number.
Composite, it is divisible by 2,7,14, and 49