No, 98 is an even number so it is divisible by 2.
No, 98 is divisible by 2; therefore, it is a composite number.
98 is the largest two digit number divisible by 7.
No, but 98 is divisible by 298/2 = 49
No. 98 is not evenly divisible by 21.
No. Any number that ends with 0, 2, 4, 6, 8 is an even number; all even numbers are divisible by 2; so none of them (except for 2 itself) can be a prime number.
No, 98 is an even number so it is divisible by 2.
yes
108 is divisible by 3.
No, 98 is divisible by 2; therefore, it is a composite number.
Oh, dude, 784 is totally divisible! It can be divided by 1, 2, 4, 7, 14, 28, 56, 112, 392, and of course, itself. So yeah, if you're looking to divide 784, you've got plenty of options. Like, it's not a high-pressure situation or anything.
No. To check for divisibility by 9 add the digits together and if this sum is divisible by 9 then so is the original number. This can be repeated until a single digit remains which must be 9 for the original number to be divisible by 9. For 98: 9 + 8 = 17 → 1 + 7 = 8 which is not 9, so 98 is not divisible by 9.
98 is divisible by two, 99 is not, so 98.
98 is the largest two digit number divisible by 7.
No, but 98 is divisible by 298/2 = 49
No, it isn't. You can always check - by adding the digits together. If the resulting number is divisible by 3, then the original number is too. In this example - 9+8=17... 17 will NOT divide by three exactly therefore 98 won't either.
Since it ends with an 8, it's an even number, which means it's divisible by 2. That's all we need, in order to know that it can't be a prime number, so it must be composite. Put that little factoid in your pocket and keep it: No even number except 2 is a prime number.