log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
The expression "log(25) log(25)" represents the square of the logarithm of 25. If we let ( x = \log(25) ), then the expression simplifies to ( x^2 ). The value of ( \log(25) ) can be calculated as ( \log(5^2) = 2\log(5) ). Thus, ( \log(25) log(25) = (2\log(5))^2 = 4(\log(5))^2 ).
how do i log in
log(5)125 = log(5) 5^(3) = 3log(5) 5 = 3 (1) = 3 Remember for any log base if the coefficient is the same as the base then the answer is '1' Hence log(10)10 = 1 log(a) a = 1 et.seq., You can convert the log base '5' , to log base '10' for ease of the calculator. Log(5)125 = log(10)125/log(10)5 Hence log(5)125 = log(10) 5^(3) / log(10)5 => log(5)125 = 3log(10)5 / log(10)5 Cancel down by 'log(10)5'. Hence log(5)125 = 3 NB one of the factors of 'log' is log(a) a^(n) The index number of 'n' can be moved to be a coefficient of the 'log'. Hence log(a) a^(n) = n*log(a)a Hope that helps!!!!!
log(36,200) = 4.558709 (rounded)log[log(36,200)] = 0.658842 (rounded)
No. Log are not alive so they can not be producers, consumers or decomposers. Decomposers will be breaking them down.
A log is considered an abiotic factor because it is a non-living component of an ecosystem. It can provide habitat for organisms and contribute to nutrient cycling, but it is not alive itself.
log(x6) = log(x) + log(6) = 0.7782*log(x) log(x6) = 6*log(x)
tom dunsdons dad and mum log log log log log log log in my buttt
No. The log of a quotient is the log of a denominator subtracted from the log of the numerator.
Not quite. The log(x/y) = log(x) - log(y) In words, this reads "The log of a quotient is the difference of the log of the numerator and the log of the denominator."
"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a
log on to
To simplify the expression log(log(n)), you can rewrite it as log(n) / log(10).
1
log(x) - log(6) = log(15)Add log(6) to each side:log(x) = log(15) + log(6) = log(15 times 6)x = 15 times 6x = 90
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.