To determine if ( b^2(c + d) ) is rational, we need to know the values of ( b ), ( c ), and ( d ). If ( b ), ( c ), and ( d ) are all rational numbers, then ( b^2 ) is rational (since the square of a rational number is rational) and ( c + d ) is also rational (as the sum of two rational numbers is rational). Therefore, the product ( b^2(c + d) ) would be rational as well. However, if any of these values are irrational, then ( b^2(c + d) ) may not be rational.
int a=2, b=3, c=4, d=5; printf ("%d/%d + %d/%d = %d/%d\n", a, b, c, d, a*d+b*c, b*d);
No. A rational plus an irrational is always an irrational.
10
No, never.
Yes. Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.
int a=2, b=3, c=4, d=5; printf ("%d/%d + %d/%d = %d/%d\n", a, b, c, d, a*d+b*c, b*d);
No. A rational plus an irrational is always an irrational.
If both numbers are rational then x plus y is a rational number
10
rational. if it can be expressed as a fraction, it is rational.
B2C ---- Business-To-Consumer.
Walmart is B2C
Yes, it is.
I do not believe that there are any rational roots.
Yes, the sum is always rational.
They add up to 17.02 which is rational number
x^2 + 11x + 6 has no rational zeros.