domain = x-values range = y-values for which x or y is a solution
domain is independent why? because its before range or also known as x/domain and y/range(x,y).
in a coordinate point, the domain is the "x" part in (x,y) say you have a point that is (5,7). the domain would be 5.
f(x)=(x/|x-3|)+1; domain is all real numbers except 3. f(x)=(x/(|x-3|+1)); domain is all real numbers.
Domain is considered the x-axis. So, to find the domain, one should to read the graph from left to right.
The domain is the (x) of the equation, and if (x) is zero then that is the domain. So yes the domain can be zero.
The domain is the x value
The domain is the x or the input
The domain of a relation is the X axis.
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
domain = x-values range = y-values for which x or y is a solution
domain is independent why? because its before range or also known as x/domain and y/range(x,y).
in a coordinate point, the domain is the "x" part in (x,y) say you have a point that is (5,7). the domain would be 5.
5
The domain of f is x is R (if imaginary roots are permitted, and there is nothing in the question to suggest otherwise). The domain of g is R excluding x = 5 So the domain of f + g is R excluding x = 5 and the domain of f/g is R excluding x = 0
x is a letter often used as a variable. It can be in the range or the domain. However, in elementary algebra, the variable x is most often used for the domain and f(x) =y for the range.