0
Is initial velocity y the same for an angled launch and a horizontal launch if you use the same projectile launcher?
Wiki User
∙ 12y ago
Yes. They will both initially be moving at the same speed.
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
How do you find vertical and horizontal components when given the initial velocity?
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
How to find the height of the projectile launch if the angle velocity and the distance are given?
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
Given the velocity of a projectile the angle of projection and the mass of the object how do you determine the distance traveled?
Given the initial velocity V, and the angle from the ground A, the total distance travelled X will be: X = 2 V2 cos(A) sin(A) / gwhere "g" is the acceleration due to gravity, on earth g is approximately 9.81 m/s2.You will notice that the mass of the object does not affect the distance traveled. We can derive this by first determining how long the projectile will be in the air. If the initial velocity is V, then the initial vertical velocity is Vsin(A). The vertical velocity will decrease at a rate of 'g' until the vertical velocity reaches zero (known as apogee), and the projectile starts falling down. The time from launch to apogee will be Vsin(A)/g.The time for the projectile to go up is the same as for the projectile to fall down again, so the total time in the airis 2Vsin(A)/g.Assuming we neglect friction, the horizontal velocity is Vcos(A) and does not change. The total distance traveled horizontally is the horizontal speed multiplied by the time spend in the air. So X = 2Vsin(A)/g * Vcos(A) = 2V2cos(A)sin(A)/g.The maximum distance is achived with an angle of 45o. The distance travelled is symmetric around this value, i.e. an angle of 50o will give the same distance as 40o, and an angle of 15owill give the same distance as 75o.
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
A certain projectil is launched with an initial speed Vo At its highest poin its speed is Vo divided by 6 What was the launch angle?
(As usual when working with this subject, we'll assume zero air resistance.)When the projectile is launched, the horizontal component of its velocity is V0cos(A).At its highest point, its vertical speed is zero; all of its speed is horizontal,and equal to the horizontal speed it had coming out of the muzzle.V0/6 = V0cos(A)cos(A) = 1/6A = cos-1(1/6) = 80.4 degrees (rounded)
What is the horizontal distance traveled by a projectile?
The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).
What is the initial direction on the projectile's velocity?
The initial direction of a projectile's velocity is typically determined by the angle at which it is launched relative to the horizontal plane. This angle will influence both the horizontal and vertical components of the velocity.
What is the horizontal displacement of a projectile?
The horizontal displacement of a projectile is the distance traveled by the projectile along the horizontal axis from its initial position to its final position. It is affected by the initial velocity of the projectile and the time it spends in motion. The horizontal displacement can be calculated using the equation: Horizontal displacement = initial velocity * time.
Is it true that the vertical component of the projectile motion of an object depend on initial velocity only?
Yes, in projectile motion, the vertical component of motion is influenced by the initial velocity in the vertical direction. The horizontal and vertical components of motion are independent of each other, with the horizontal component being influenced by the initial velocity in the horizontal direction.
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
The horizontal speed of the projectile remains constant as there is no force acting in the horizontal direction to change it. Therefore, the horizontal speed of the projectile after 3 seconds will remain at 4 m/s.
What is the horizontal range of a projectile initial velocity is doubled?
If the initial velocity of a projectile is doubled, the horizontal range will also double. This is because the horizontal distance traveled by a projectile is directly proportional to the square of its initial velocity.
How does a projectille differ from an object in a free fall?
A projectile has an initial forward velocity.
What do you need to know to be able to determine how far a projectile travels horizontally?
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the time of flight and then multiply it by the horizontal component of the initial velocity to find the horizontal distance traveled.
How is the horizontal component of velocity for a projectile affected by the vertical component?
The horizontal component of velocity for a projectile is not affected by the vertical component. They are independent of each other. The horizontal velocity remains constant as long as there are no external forces acting on the projectile.
What minimum initial velocity must a projectile have to reach a target 90km away?
The minimum initial velocity required for a projectile to reach a target 90 km away depends on the angle at which the projectile is launched, as well as the effects of air resistance and other factors. A common approach is to use projectile motion equations to determine the initial velocity needed for the projectile to cover the horizontal distance of 90 km in the given conditions.
What do you need to know to determine how far a projectile travels horizontally?
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it is launched, and the acceleration due to gravity. The horizontal range of the projectile can be calculated using the formula: range = (initial velocity squared * sin(2*launch angle)) / acceleration due to gravity.
A shell is fired from the ground with an initial velocity of 1600m s at an angle of 64 to the horizontal What is the shells horizontal range?
Using the projectile motion equations and given the initial velocity and angle, we can calculate the time the shell is in the air. Then, we can find the horizontal range by multiplying the time of flight by the horizontal component of the initial velocity. The horizontal range in this case is about 1056 meters.
