0
What else can I help you with?
How do you find vertical and horizontal components when given the initial velocity?
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
How to find the height of the projectile launch if the angle velocity and the distance are given?
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
Given the velocity of a projectile the angle of projection and the mass of the object how do you determine the distance traveled?
Given the initial velocity V, and the angle from the ground A, the total distance travelled X will be: X = 2 V2 cos(A) sin(A) / gwhere "g" is the acceleration due to gravity, on earth g is approximately 9.81 m/s2.You will notice that the mass of the object does not affect the distance traveled. We can derive this by first determining how long the projectile will be in the air. If the initial velocity is V, then the initial vertical velocity is Vsin(A). The vertical velocity will decrease at a rate of 'g' until the vertical velocity reaches zero (known as apogee), and the projectile starts falling down. The time from launch to apogee will be Vsin(A)/g.The time for the projectile to go up is the same as for the projectile to fall down again, so the total time in the airis 2Vsin(A)/g.Assuming we neglect friction, the horizontal velocity is Vcos(A) and does not change. The total distance traveled horizontally is the horizontal speed multiplied by the time spend in the air. So X = 2Vsin(A)/g * Vcos(A) = 2V2cos(A)sin(A)/g.The maximum distance is achived with an angle of 45o. The distance travelled is symmetric around this value, i.e. an angle of 50o will give the same distance as 40o, and an angle of 15owill give the same distance as 75o.
Can the effect of initial velocity on final velocity be predicted?
Well, (final velocity) = (initial velocity) + (acceleration x time)
What is the horizontal distance traveled by a projectile?
The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).
What do the horizontal motions of a projectile have in common?
The horizontal motions of a projectile are independent of its vertical motion. This means that the horizontal velocity remains constant and unaffected by gravity. Additionally, the horizontal distance traveled by a projectile is determined by the initial horizontal velocity and the time of flight.
What is the initial direction on the projectile's velocity?
The initial direction of a projectile's velocity is typically determined by the angle at which it is launched relative to the horizontal plane. This angle will influence both the horizontal and vertical components of the velocity.
What is the horizontal displacement of a projectile?
The horizontal displacement of a projectile is the distance traveled by the projectile along the horizontal axis from its initial position to its final position. It is affected by the initial velocity of the projectile and the time it spends in motion. The horizontal displacement can be calculated using the equation: Horizontal displacement = initial velocity * time.
Is it true that the vertical component of the projectile motion of an object depend on initial velocity only?
Yes, in projectile motion, the vertical component of motion is influenced by the initial velocity in the vertical direction. The horizontal and vertical components of motion are independent of each other, with the horizontal component being influenced by the initial velocity in the horizontal direction.
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
The horizontal speed of the projectile remains constant as there is no force acting in the horizontal direction to change it. Therefore, the horizontal speed of the projectile after 3 seconds will remain at 4 m/s.
What is the horizontal range of a projectile initial velocity is doubled?
If the initial velocity of a projectile is doubled, the horizontal range will also double. This is because the horizontal distance traveled by a projectile is directly proportional to the square of its initial velocity.
How does a projectille differ from an object in a free fall?
A projectile has an initial forward velocity.
What do you need to know to be able to determine how far a projectile travels horizontally?
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the time of flight and then multiply it by the horizontal component of the initial velocity to find the horizontal distance traveled.
What is the formula for a horizontal launched projectile?
The formula for the horizontal distance traveled by a horizontally launched projectile is: range = initial velocity * time. This formula assumes that there is no air resistance and that the projectile is launched horizontally.
How do you determine the initial velocity in projectile motion?
To determine the initial velocity in projectile motion, you can use the equation v (x y) / t, where v is the initial velocity, x is the horizontal distance traveled, y is the vertical distance traveled, and t is the time taken.
How is the horizontal component of velocity for a projectile affected by the vertical component?
The horizontal component of velocity for a projectile is not affected by the vertical component. They are independent of each other. The horizontal velocity remains constant as long as there are no external forces acting on the projectile.
