find out sqrt of area of square,say it B.NOW,AREA OF TRIANGLE WILL BE-
A=(B^2)/2=AREA OF SQR/2
A right angle triangle with two side lengths that match that of an equivalent square will have exactly half the area of the square.
Pythagoras' theorem states that for any right angle triangle the square of its hypotenuse is equal to the squares of its 2 sides:- a2+b2 = c2 whereas a and b are the sides of the triangle with c being its hypotenuse or longest side
You either need to find the area of the triangle and subtract it from that of the rectangle OR you find the areas of the bits of the rectangle that are outside the triangle and add them together. Without more details of the triangle, it is not possible to give a more detailed answer.
Comparing the areas: The larger triangle has an areas of 102 sq in the smaller 60 sq in.
There are different methods to work out the exact areas for different shapes. These work for regular shapes or ones that can be built up from regular shapes (such as a rectangle with a semicircle sitting on top). It is usually not possible to work out the exact area of an irregular shape but should be possible to estimate areas of any 2-d shape. One method is given below: Mark the shape out on a grid (a sheet of paper with squares marked out on it). Count all squares where more than half the square is inside your 2-d shape = X. Count the number of squares where (about) half is inside your shape = Y. Ignore all squares where less than half is inside your shape. Then X + Y/2 will be a good estimate of the area of your shape. The smaller the squares in the grid, the more accurate the estimate but also, the greater the number of squares that will have to be counted.
The square of the hypotenuse of right triangle is equal to the sum of the squares of the two adjacent sides.
Those areas bounded by the Artic Circle
A right angle triangle with two side lengths that match that of an equivalent square will have exactly half the area of the square.
The square of the hypoentuse is equal to the sum of the squares of the other two sides.
it is possible, if the triangle is bigger than the rectangle, for example the rectangle has a base of 5 and height of 2-- so the area is 10; and then the triangle has a base of 5 and a height of 4-- the area is also 10.
Pythagoras' theorem states that for any right angle triangle the square of its hypotenuse is equal to the squares of its 2 sides:- a2+b2 = c2 whereas a and b are the sides of the triangle with c being its hypotenuse or longest side
The ratio is 16 to 81.
The sum of the areas of the two squares on the legs of a triangle (a and b), where the angle between sides a and b is 90 degrees, equals the area of the square on the hypotenuse (c). a2 + b2 = c2
The area of a triangle is half the base times the height, so obviously the areas will be the same if these figures are identical, but I doubt it is possible to have such correspondence between any two of the triangles you mention! Consider mapping a right triangle to an isosceles - I can't keep the altitude constant.
You either need to find the area of the triangle and subtract it from that of the rectangle OR you find the areas of the bits of the rectangle that are outside the triangle and add them together. Without more details of the triangle, it is not possible to give a more detailed answer.
Comparing the areas: The larger triangle has an areas of 102 sq in the smaller 60 sq in.
Two major areas where Pascal's Triangle is in Algebra and Probability.