Yes but not a square (or rectangle). A quadrilateral with an area of 16 sq units must have sides of at least 4 units and so a perimeter of at least 16 units.
However, a circle of perimeter 15 units will enclose an area of 17.905 sq units (to 3 dp) so an ellipse of 15 units' perimeter will meet the requirements.
a 4*5 rectangle.
Bigger than what ? Smaller than what ? If you have a certain perimeter and you want to cram the most area inside it, or if you have a certain area and you want to enclose it in the shortest perimeter, then you must make the perimeter circular. If you have only a limited number of fence posts and a circular perimeter isn't practical, then you make the perimeter square.
To draw a shape with the same area and perimeter, decide what shape you want to draw, then take the equations for area and perimeter and make them equal, and then solve what the various side lengths have to be. For instance, the area of a square is L2 where L is the side length, and the perimeter of a square is Lx4 We want them equal, so L2=Lx4 Dividing both sides by L gives us L=4, so if I draw a square with side length 4, it will have the same area and perimeter.
Oh, dude, let me break it down for you. So, to make a shape with an area of 9, you could have a square with sides of length 3. But to have a perimeter of 14, you'd need a rectangle with sides of length 4 and 3. So, yeah, you can't have both at the same time. Like, it's just not gonna happen, man.
Make it 2 wide and 21 long and you've got it.
Actually it is possible.
Yes a 2 by 6 rectangle for example.
Yes if you
Yes. Use excel with 18 boxes. Offsetting the boxes will get you the right answer.
a 4*5 rectangle.
Bigger than what ? Smaller than what ? If you have a certain perimeter and you want to cram the most area inside it, or if you have a certain area and you want to enclose it in the shortest perimeter, then you must make the perimeter circular. If you have only a limited number of fence posts and a circular perimeter isn't practical, then you make the perimeter square.
No, because you would need a calculation os 3 to make a calculation of 6, and 18 and 20 aren't friendly to one another!
Yes, it is possible for the area to be smaller than the perimeter. In geometric terms, the area of a shape is the measure of the space inside the shape, while the perimeter is the sum of the lengths of all the sides. For certain shapes, such as rectangles with very elongated proportions, it is possible for the perimeter to be larger than the area.
if your perimeter totals the same as 4 times pi then the maximum area that can be encompassed is equal to the perimeter. This is done by forming a circle. if you change the shape of the circle then the area will become smaller than the perimeter(circumference) if you make the circumference of the circle smaller then you will definitely decrease the area faster than you would the perimeter if you make the perimeter bigger then you will definitely increase the area faster than you would the perimeter.
To draw a shape with the same area and perimeter, decide what shape you want to draw, then take the equations for area and perimeter and make them equal, and then solve what the various side lengths have to be. For instance, the area of a square is L2 where L is the side length, and the perimeter of a square is Lx4 We want them equal, so L2=Lx4 Dividing both sides by L gives us L=4, so if I draw a square with side length 4, it will have the same area and perimeter.
Oh, dude, let me break it down for you. So, to make a shape with an area of 9, you could have a square with sides of length 3. But to have a perimeter of 14, you'd need a rectangle with sides of length 4 and 3. So, yeah, you can't have both at the same time. Like, it's just not gonna happen, man.
Make it 2 wide and 21 long and you've got it.