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Yes but not a square (or rectangle). A quadrilateral with an area of 16 sq units must have sides of at least 4 units and so a perimeter of at least 16 units.

However, a circle of perimeter 15 units will enclose an area of 17.905 sq units (to 3 dp) so an ellipse of 15 units' perimeter will meet the requirements.

Q: Is it possible to make a shape out of the area of 16 and a perimeter of 15?

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Yes.

a 4*5 rectangle.

Bigger than what ? Smaller than what ? If you have a certain perimeter and you want to cram the most area inside it, or if you have a certain area and you want to enclose it in the shortest perimeter, then you must make the perimeter circular. If you have only a limited number of fence posts and a circular perimeter isn't practical, then you make the perimeter square.

To draw a shape with the same area and perimeter, decide what shape you want to draw, then take the equations for area and perimeter and make them equal, and then solve what the various side lengths have to be. For instance, the area of a square is L2 where L is the side length, and the perimeter of a square is Lx4 We want them equal, so L2=Lx4 Dividing both sides by L gives us L=4, so if I draw a square with side length 4, it will have the same area and perimeter.

Make it 2 wide and 21 long and you've got it.

Related questions

Yes.

Actually it is possible.

Yes a 2 by 6 rectangle for example.

Yes if you

Yes. Use excel with 18 boxes. Offsetting the boxes will get you the right answer.

a 4*5 rectangle.

Bigger than what ? Smaller than what ? If you have a certain perimeter and you want to cram the most area inside it, or if you have a certain area and you want to enclose it in the shortest perimeter, then you must make the perimeter circular. If you have only a limited number of fence posts and a circular perimeter isn't practical, then you make the perimeter square.

No, because you would need a calculation os 3 to make a calculation of 6, and 18 and 20 aren't friendly to one another!

if your perimeter totals the same as 4 times pi then the maximum area that can be encompassed is equal to the perimeter. This is done by forming a circle. if you change the shape of the circle then the area will become smaller than the perimeter(circumference) if you make the circumference of the circle smaller then you will definitely decrease the area faster than you would the perimeter if you make the perimeter bigger then you will definitely increase the area faster than you would the perimeter.

To draw a shape with the same area and perimeter, decide what shape you want to draw, then take the equations for area and perimeter and make them equal, and then solve what the various side lengths have to be. For instance, the area of a square is L2 where L is the side length, and the perimeter of a square is Lx4 We want them equal, so L2=Lx4 Dividing both sides by L gives us L=4, so if I draw a square with side length 4, it will have the same area and perimeter.

Make it 2 wide and 21 long and you've got it.

You don't mean the "maximum perimeter".You can keep the perimeter of 80 feet, and shape the ring to make the areaas close to zero as you want it (but you can never make it exactly zero).What you really want to ask is: What's the maximum areayou can make with aperimeter of 80 feet ?If you play with it for a while ... which you really should do ... you'll find thatthe greatest area you can make with any perimeter is a circle, and the nextgreatest is a square, with 1/4 of the perimeter on each side.So for your boxing ring and 80 feet of ropes, the square is (20-ft x 20-ft), andthe area is 400 square feet. That's the biggest possible area.