No, it is not.
Pi / 5 would be in Quadrant I.
No
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
2r + (2pi r)/4 or 2r x (1 + pi/4) eg radius 3 units, circumference 6 pi units, arc of quadrant 1.5 pi units, plus 2 x radius ie 6 so P = (1.5 pi + 6) units (approx 10.7)
The measure of an angle whose cosine is 0.5 is 60 degrees (or (\frac{\pi}{3}) radians) in the first quadrant. Additionally, in the context of the unit circle, the angle can also be 300 degrees (or (\frac{5\pi}{3}) radians) in the fourth quadrant.
Pi / 5 would be in Quadrant I.
Pi / 5 would be in Quadrant I.
No
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
8.3 Radians? is in the second quadrant. 8.3/pi*180 is about 115. 115 is in the second quadrant.
In a circle of radius, r, perimeter of quadrant = pi*r/2 + 2r = r*(pi/2 + 2)
If you the radius of the circle is r then the perimeter of a quadrant = r*(2 + pi/2).
9.3333
Circumference of a circle = 2 * pi * r pi = 3.1415926535897932384626433832795 r= radius of circle Hence Circumference of a Quadrant = 2 * pi * r / 4 = pi * r / 2 = 0.5 * pi * r For more accurate value of pi, please refer: http://en.wikipedia.org/wiki/Pi
If the radius of the circle is r, then the area of the quadrant is 0.25*pi*r^2
If you know the radius then pi r2/4
The angles in quadrant one measure between 0 degrees and 90 degrees. In radians, that's between 0 and pi/2. Quadrant one is the quadrant where both X and Y (or cosine theta and sine theta) are positive.