No, it is not.
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Pi / 5 would be in Quadrant I.
No
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
2r + (2pi r)/4 or 2r x (1 + pi/4) eg radius 3 units, circumference 6 pi units, arc of quadrant 1.5 pi units, plus 2 x radius ie 6 so P = (1.5 pi + 6) units (approx 10.7)
Oh, what a happy little question! To find the area of a quadrant, you simply take the area of a full circle (πr^2) and divide it by 4, since a quadrant is one-fourth of a circle. Just remember to use the radius of the circle to calculate the area of the quadrant. Happy calculating!