Yes, plus 1 is consider as positive one (+1). All positive and negative numbers are considered as integer.
x + 1 would be a consecutive integer where x is an integer.
1
-2 -1 0 1 2
Any positive odd integer can be expressed in the form of ( 2k + 1 ), where ( k ) is a non-negative integer. When dividing this expression by 6, the possible remainders are 1, 3, and 5, corresponding to the cases where ( k ) is congruent to 0, 1, or 2 modulo 3, respectively. Thus, an odd integer can be represented as ( 6q + 1 ), ( 6q + 3 ), or ( 6q + 5 ) for some integer ( q ). This shows that every positive odd integer fits one of these forms.
zero?
x + 1 would be a consecutive integer where x is an integer.
x+2
1
n2 + 1 where n is an integer.
an integer plus and integer will always be an integer. We say integers are closed under addition.
It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.
-2 -1 0 1 2
2
This question can be expressed algebraically as: (1/n) + (1/(2n)) + 2 = 23, (1/n) + (1/(2n)) =21, ((1+2)/(2n)) = 21, (3/(2n)) = 21, or 2n = (3/21), 2n = (1/7), so n = (1/14). This, by the way, is an elementary algebraic proof that the solution to the above relation is (1/14). Anyway, to answer the question, reread the question: "[What integer is such that] the reciprocal of the integer...". notice, the reciprocal of (1/14) is 14, which is the integer in question! ^_^
zero?
The answer, in any integer base greater than 2, is 2.
-2, -1, 0 ,1