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Q: Is x plus 1 considered a consecutive even integer?

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x+3 and x+4 would be consecutive integers.

If both x and y are integers, then x plus y is always an integer, otherwise not.

10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.

11 plus 12 plus 13 can satisfy this

The absolute value of an integer is found by ignoring its sign (plus or minus).

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It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.

x+2

Only if x is already an integer. For any integer x, 2x + 2 will be an even integer.

Yes, plus 1 is consider as positive one (+1). All positive and negative numbers are considered as integer.

x+3 and x+4 would be consecutive integers.

an integer plus and integer will always be an integer. We say integers are closed under addition.

Every integer is either even (divisible by 2) or odd (not divisible by 2). Since an even number plus 1 is odd and an odd number plus one is even, because 1 does not divide 2. We know (n + 4) is odd. The next integer is (n + 4 + 1) = (n + 5), because an odd number plus 1 is even, (n + 5) is even. The integer after (n + 5) is (n + 6), since (n + 5) we know is even, (n + 6) must be odd. Since (n + 6) is the smallest integer that is greater than (n + 4) and is odd, so (n + 6) is the next odd integer.

This is (3x +2)2 so if x is an integer/3, this expression is the square of an integer so cannot be prime. Anything else, and it's not even an integer.

An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Even plus odd is odd.

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No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.

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