x+2
an integer plus and integer will always be an integer. We say integers are closed under addition.
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.
78 + 34 is 112, which is an integer, not a fraction.
You will get a positive integer. If you subtract a negative number, you will be adding it. I think of it like 2 minuses equals a plus. :P
First, an equation is needed. We will designate the first integer as N, and the second as N + 2. The sum of the two numbers is 176, so the equation should look like this:N + N + 2 = 176Now it needs to be added:2N + 2 = 176Now both sides need to be subtracted by 2:2N = 174Now both sides need to be divided by 2:N = 87Therefore, the first integer is 87. Since the second integer is designated by N + 2, and N is equal to 87, the second integer is 87 plus 2, which is equal to 89.So the two consecutive odd integers whose sum is 176, are 87 and 89.
x + 1 would be a consecutive integer where x is an integer.
x+3 and x+4 would be consecutive integers.
It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.
m+6
Every integer is either even (divisible by 2) or odd (not divisible by 2). Since an even number plus 1 is odd and an odd number plus one is even, because 1 does not divide 2. We know (n + 4) is odd. The next integer is (n + 4 + 1) = (n + 5), because an odd number plus 1 is even, (n + 5) is even. The integer after (n + 5) is (n + 6), since (n + 5) we know is even, (n + 6) must be odd. Since (n + 6) is the smallest integer that is greater than (n + 4) and is odd, so (n + 6) is the next odd integer.
5*x = 4*(x+2) + 3 so 5x = 4x + 8 + 3 = 4x + 11 Subtracting 4x from both sides: x = 11 So the two integers are 11 and 13.
an integer plus and integer will always be an integer. We say integers are closed under addition.
2
zero?
It is 2.
Closure of the set of integers under addition.
If both x and y are integers, then x plus y is always an integer, otherwise not.