Yes.
The normal distribution.
Mean
In the normal distribution, the mean and median coincide, and 50% of the data are below the mean.
A normal distribution is symmetrical; the mean, median and mode are all the same, on the line of symmetry (middle) of the graph.
Yes, the mean (and median and mode) is the 50th percentile of any normal distribution.
In a normal distribution, the mean, median, and mode are all equal. Therefore, if the mean is 40, the median is also 40. This property holds true for any normal distribution regardless of its specific values.
Mean, median, and mode are all equal in a normal distribution.
Yes, in a normal distribution, the mean is always equal to the median. This is because the normal distribution is symmetric around its mean, meaning that the values are evenly distributed on both sides. As a result, the central tendency measured by both the mean and the median coincides at the same point.
The mean, median, and mode of a normal distribution are equal; in this case, 22. The standard deviation has no bearing on this question.
In a normal distribution, the mean, median, and mode are all equal. Therefore, if both the mean and the mode are 25, the median would also be 25. This property is a defining characteristic of normal distributions.
The normal distribution.
True. You can find many references including wikipedia on the Normal distribution on the internet.
In a symmetric distribution, the mean and median will always be equal. This is because symmetry implies that the distribution is balanced around a central point, which is where both the mean (the average) and the median (the middle value) will fall. Therefore, in perfectly symmetric distributions like the normal distribution, the mean, median, and mode coincide at the center. In practice, they may be approximately equal in symmetric distributions that are not perfectly symmetrical due to rounding or sampling variability.
Mean
Yes, and they WILL be if the distribution is symmetrical.
No.
132. You're the the one that stated "normal distribution", thus the same.