Yes because the square root of 16 is 4
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
The square root of 18, rounded to the nearest integer, is 4.
Yes, and it is 4
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.
The square root of 4 is 2 (and -2) and is an integer.
Yes, because the square root of 16 is 4 and as a whole number it is an integer
Yes because the square root of 16 is 4
The square root of an integer is a CYCLOTOMIC integer.
no.No. The square root of 5 is an irrational number. The two closest numbers with integer square roots are 4 (with a square root of 2) and 9 (with a square root of 3). Since there are no integers between 2 and 3 and 5 lies between 4 and 9, it's pretty evident that it can't have an integer square root.
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
The square root of 18, rounded to the nearest integer, is 4.
Yes, and it is 4
4.123105626 rounds down to 4
Yes. For example, the square root of 1 is 1, and the square root of 4 is 2.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
The square root of 3 is not an integer.