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What do the negative sign in front of the number 3s means in algebraic expression?
It means that the term for which 3 is the coefficient is meant to be subtracted.
What is 3s minus 9 as a verbal expression?
Nine less than three times a number; the initial number being represented by s.
What is 3s plus 1?
3s + 1
What is a 3S facility?
3S Facility simply means sales, services and spares
What is 12r-15s-r plus 3s?
12r - 15s - r + 3s = 11r -12s
Use five 3s to write an expression whose value is 29?
33 + (3 + 3)/3
What do the negative sign in front of the number 3s means in algebraic expression?
It means that the term for which 3 is the coefficient is meant to be subtracted.
Use an exponent to write a expression with five 3s that has a value of 0?
3^3 - (3 x 3 x 3) is zero.
What is 3s minus 9 as a verbal expression?
Nine less than three times a number; the initial number being represented by s.
What is 3s plus 1?
3s + 1
What is 135 equals 3s plus 15?
135=3s +15 120=3s 40=s
What is the least common multiple of the monomial a 3s and s2?
Well, honey, the least common multiple of a monomial like a^3s and s^2 is simply a^3s^2. You just gotta take the highest power of each variable that appears in either monomial, slap 'em together, and there you have it. Math made sassy.
how many 3 are in 6037234789333333333333333333333333363?
28 3s
What is a 3S facility?
3S Facility simply means sales, services and spares
How do you do -7 equals 3s-1?
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
What is 4 3s written as a rational number?
4 3s = 4*3 = 12, which is a rational number.
How do you solve an inequality with a negative coefficient?
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
