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What do the negative sign in front of the number 3s means in algebraic expression?
It means that the term for which 3 is the coefficient is meant to be subtracted.
What is 3s minus 9 as a verbal expression?
Nine less than three times a number; the initial number being represented by s.
What is 3s plus 1?
3s + 1
What is a 3S facility?
3S Facility simply means sales, services and spares
How many 3s go into 140?
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
Use five 3s to write an expression whose value is 29?
33 + (3 + 3)/3
What do the negative sign in front of the number 3s means in algebraic expression?
It means that the term for which 3 is the coefficient is meant to be subtracted.
Use an exponent to write a expression with five 3s that has a value of 0?
3^3 - (3 x 3 x 3) is zero.
What is 3s minus 9 as a verbal expression?
Nine less than three times a number; the initial number being represented by s.
What is 3s plus 1?
3s + 1
What is 135 equals 3s plus 15?
135=3s +15 120=3s 40=s
how many 3 are in 6037234789333333333333333333333333363?
28 3s
What is a 3S facility?
3S Facility simply means sales, services and spares
How many 3s go into 140?
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
How do you do -7 equals 3s-1?
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
What is 4 3s written as a rational number?
4 3s = 4*3 = 12, which is a rational number.
How do you solve an inequality with a negative coefficient?
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
