Yes
displacement reaction............ u people have to find the answers instead asking others without shame..............
81.93%
moles of Al=4.40 g/26.9815 g/mol=0.163 moles cl2=15.4g/70.906g/mol=0.217 the ratio is 2:3 cl2 is the limiting reagent
2Al(s) + 6HCl(aq) = 2AlCl3(aq) + 3H2(g). The molar ratios are 2:6 :: 2:3 This means that two moles of aluminium will react to completion with exactly six moles of hydrocchloric acid. At completion there will be two moles of aluminium chloride and three moles of hydrogen gas. So if you had 8 moles of hydrochloric acid and only 2 moles of aluminium, then the aluminium would be the limiting reactant, because from the 8 moles hydrochloric acid you are using only six moles, leaving two moies on hydrochloric acid unreacted. Conversely, if you had 3 moles of Al and 6 moles HCl , then the HCl would be the limiting reactant. Because the 6 moles of acid would only react with two moles of Al leaving one mole Al unreacted.
Thermite is a mixture of aluminum powder and a metal oxide, commonly iron(III) oxide (Fe2O3). The chemical reaction can be represented by the equation: 2Al + Fe2O3 → 2Fe + Al2O3. This reaction produces intense heat and molten iron, which is the basis for thermite's applications in welding and metal cutting.
No, the chemical equation is not balanced. Balancing it requires adjusting the coefficients of the compounds so that the number of each type of atom is the same on both sides of the equation.
This is a single displacement reaction, also known as a replacement reaction or a substitution reaction. In this reaction, aluminum (Al) replaces nickel (Ni) in nickel(II) bromide (NiBr2) to form aluminum bromide (AlBr3) and nickel (Ni).
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
2Al + N2 ----> 2AlN
In the reaction Al3 Br2 -> 2 AlBr3, aluminum (Al) is oxidized from 0 to +3 (loses electrons) as it goes from Al3 to AlBr3. Bromine (Br) is reduced from 0 to -1 (gains electrons) as it goes from Br2 to AlBr3.
The balanced equation for aluminum reacting with sulfuric acid is 2Al + 3H2SO4 -> Al2(SO4)3 + 3H2.
2Fe+3Cl2------>2FeCl3
The balanced chemical equation is: 2HNO3 + Al2O3 --> 2Al(NO3)3 + 3H2O
When nitric acid reacts with aluminum, it produces aluminum nitrate, nitrogen dioxide gas, and water. The balanced chemical equation for this reaction is: 2Al + 6HNO3 -> 2Al(NO3)3 + 3H2O + 3NO2
The balanced equation should be 2Al + 6HCl -> 2AlCl3 + 3H2. Therefore, the coefficient of HCl is 6.
2Al + 3Cl2 ---> 2AlCl3
6HNO3 (aq) + 2Al (s) → 3H2(g) + 2Al(NO3)3 (aq)