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Find the three consecutive even integers such that if the largest integer is subtracted from 4 time the smallest the result is 6 more than twice the middle integer?
Suppose the three integers are 2x-2, 2x and 2x+2 for some integer x. Then 4*(2x-2) - (2x+2) = 2*2x + 6 or 8x - 8 - 2x - 2 = 4x + 6 => 6x - 10 = 4x + 6 => 2x = 16 so that x = 8. So the numbers are 14, 16 and 18.
Which sequence of fx equals 2x plus 2 has integer input values?
f(x)=2x+2. Put in 0, 1/2, 1, 3/2, 2... and you will get integer values. That is for the domain. The numbers you get when you put that in are the range integral values.
Is an even number times any number always even?
YES Even Number by definition any integer that can be divided exactly by 2. To get an even number, multiply an integer by 2 or in mathematical statement it is 2n. An even number (2x) is multiplied to any number (y) is 2x (y). So, by associative principle of multiplication 2x(y) = 2 (x*y). If (x*y) now represents any integer then 2(x*y)= 2n. And 2n is an even number.
What is the two consecutive even integers whose sum is 90?
let x = integer and x + 2 next consecutive even integer x +(x +2) = 90 2x + 2 = 90 2x + 88 x = 44 and x+2 = 46 44 and 46
What two consecutive even positive integers equal 624?
Let x = first even integer then x + 2 = next even integer sum: x + x + 2 = 624 2x + 2 = 624 2x = 622 x = 311 x + 2 = 313 NOTICE the values are ODD not EVEN so there is no solution
