Only if x is already an integer.
For any integer x, 2x + 2 will be an even integer.
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Suppose the three integers are 2x-2, 2x and 2x+2 for some integer x. Then 4*(2x-2) - (2x+2) = 2*2x + 6 or 8x - 8 - 2x - 2 = 4x + 6 => 6x - 10 = 4x + 6 => 2x = 16 so that x = 8. So the numbers are 14, 16 and 18.
f(x)=2x+2. Put in 0, 1/2, 1, 3/2, 2... and you will get integer values. That is for the domain. The numbers you get when you put that in are the range integral values.
YES Even Number by definition any integer that can be divided exactly by 2. To get an even number, multiply an integer by 2 or in mathematical statement it is 2n. An even number (2x) is multiplied to any number (y) is 2x (y). So, by associative principle of multiplication 2x(y) = 2 (x*y). If (x*y) now represents any integer then 2(x*y)= 2n. And 2n is an even number.
let x = integer and x + 2 next consecutive even integer x +(x +2) = 90 2x + 2 = 90 2x + 88 x = 44 and x+2 = 46 44 and 46
Let x = first even integer then x + 2 = next even integer sum: x + x + 2 = 624 2x + 2 = 624 2x = 622 x = 311 x + 2 = 313 NOTICE the values are ODD not EVEN so there is no solution