No.
2X^2 - 32 = 0 2X^2 = 32 X^2 = 16 X = +/- 4 yes, (X-4) would be a factor, as...... x-4 = 0 X = 4 or 2x2 - 32 = 2(x2 - 16) = 2(x - 4)(x + 4)
x2 - 2x = x(x-2)
x(x + 2)
4
-4
2x(x^2+x-6)
x(x - 2)
(2x - 3)(x + 2)
(x - 2)(2x + 3)
8
2x2 + 6xy = 2x (x + 3y)