No.
2(x-32)(x+60)
4(x^2 + 2x + 8)
Factorise: 5x2 + 2x - 192 = (x - 6)(5x + 32) = 0; whence, x = 6 or -6.4.
-6x-32 = 2x -6x-2x = 32 -8x = 32 x = -4
No.
2X^2 - 32 = 0 2X^2 = 32 X^2 = 16 X = +/- 4 yes, (X-4) would be a factor, as...... x-4 = 0 X = 4 or 2x2 - 32 = 2(x2 - 16) = 2(x - 4)(x + 4)
2(x-32)(x+60)
16 is an even, square, two-digit factor of 32.
(x - 8)(x - 4)
(x - 8)(3x + 4)
4(x^2 + 2x + 8)
Factorise: 5x2 + 2x - 192 = (x - 6)(5x + 32) = 0; whence, x = 6 or -6.4.
-6x-32 = 2x -6x-2x = 32 -8x = 32 x = -4
-2x-2x-2x-2x-2=-32
(b + 8)(b + 4)
2x+32 = 1 2x = 1-32 2x = -31 x = -15.5