Yes. Remember it like this: X comes before Y (alphabetically). D comes before R {Domain & Range}
domain = x-values range = y-values for which x or y is a solution
domain is independent why? because its before range or also known as x/domain and y/range(x,y).
in a coordinate point, the domain is the "x" part in (x,y) say you have a point that is (5,7). the domain would be 5.
f(x)=(x/|x-3|)+1; domain is all real numbers except 3. f(x)=(x/(|x-3|+1)); domain is all real numbers.
The function ( f(x) = 4x ) is a linear function. Its domain includes all real numbers, as there are no restrictions on the values that ( x ) can take. Therefore, the domain of ( f(x) ) is ( (-\infty, \infty) ).
The domain is the (x) of the equation, and if (x) is zero then that is the domain. So yes the domain can be zero.
The domain is the x value
The domain is the x or the input
The domain of a relation is the X axis.
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
domain = x-values range = y-values for which x or y is a solution
domain is independent why? because its before range or also known as x/domain and y/range(x,y).
in a coordinate point, the domain is the "x" part in (x,y) say you have a point that is (5,7). the domain would be 5.
5
The domain of f is x is R (if imaginary roots are permitted, and there is nothing in the question to suggest otherwise). The domain of g is R excluding x = 5 So the domain of f + g is R excluding x = 5 and the domain of f/g is R excluding x = 0
x is a letter often used as a variable. It can be in the range or the domain. However, in elementary algebra, the variable x is most often used for the domain and f(x) =y for the range.