To determine if ( xy^2 ) is a function, we need to understand the context in which it's used. If we treat ( y ) as a dependent variable and ( x ) as the independent variable, ( y ) can take on multiple values for a single ( x ) (for example, both positive and negative values of ( y ) can satisfy the equation ( y^2 = \frac{z}{x} ) for some constant ( z )). Therefore, ( xy^2 ) does not define ( y ) as a function of ( x ) in general situations, as it can produce multiple outputs for a single input.
No.
Whooop!
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
-5xy2 + 12xy2 = (-5 + 12)xy2 = 7xy2
x3+xy-x2y2=x(x2+y-xy2)
xy2
No.
15x2y2-9xy3 As x2y2 = x xy2 and xy3 = xy2 y then xy2 is in both term you can first factorize 15x2y2-9xy3 = xy2(15x-9y) as 15=3x5 and 9=3x3 15x2y2-9xy3 = 3xy2(5x-3y) and that it !
xy2
xy
The compound with the formula XY2 consists of one atom of element X and two atoms of element Y.
xy
The GCF is xy
48
Whooop!
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
3 * 3 * 5 * x * y * y = 45xy2