2 in 7.
Drawing one red ball out of a bag that contains 3 red balls and 4 green balls is 3 in 7. If we are to randomly select one ball out of the bag and replace it (I assume with the same ball) then there are still 3 red balls and 4 green balls. The odds are still 3 in 7. It doesn't matter how many times you draw. Every time you draw a ball you have a 3 in 7 chance of pulling out a red ball.
3/12*3/11 = 9/132, or 6.818%.
There are 18 Green balls and 12 Blue balls. You have to pick 2 blue balls, so the green balls don't matter. You can pick 1 blue ball on 12 ways. The second ball you can pick on 11 ways (because there are 11 balls left). 12 * 11 = 132. So you can pick it on 132 ways. ;)
three to make 4 blue and 4 red balls. That means there's an equal chance or a 1 in 2 chance.
The probability is zero, because there are no red balls in the bag.
Drawing one red ball out of a bag that contains 3 red balls and 4 green balls is 3 in 7. If we are to randomly select one ball out of the bag and replace it (I assume with the same ball) then there are still 3 red balls and 4 green balls. The odds are still 3 in 7. It doesn't matter how many times you draw. Every time you draw a ball you have a 3 in 7 chance of pulling out a red ball.
3/12*3/11 = 9/132, or 6.818%.
there is no timer ball in leaf green
good - 8/19 bad - 7/19 neither - 4/19
It is 1/7 if a ball is selected at random.
Dark Balls don't exist.
6/10 or reduced is 3/5
There are 18 Green balls and 12 Blue balls. You have to pick 2 blue balls, so the green balls don't matter. You can pick 1 blue ball on 12 ways. The second ball you can pick on 11 ways (because there are 11 balls left). 12 * 11 = 132. So you can pick it on 132 ways. ;)
Based on the information in the table, it can be concluded that the red ball has the highest weight while the green ball has the lowest weight. The blue ball falls in between the red and green balls in terms of weight.
ans : 3720
Level 3
3