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Suppose width = Wthen length, L = 2W + 7

So preimeter = 2*(L + W) = 2*(2W + 7 + W) = 6W + 14 = 344

Therefore 6W = 330 => W = 55 yards

and so L = 2W + 7 = 117 yards.

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Q: Length of rectangular field is 7 yards longer than double the width. if perimeter of rectangle is 344 yards what are its dimensions?
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