If you mean:
Lim(x→2) 3x + 1
Then the answer is 7
If you mean something else, then you'll need to clarify your question.
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x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
X2+3x+x+3=x(x+1)+3(x+1)=(x+3)(x+1)
x2 + 3x + 2 factors into (x + 1) (x + 2)
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
x2 + 3px + p = 0 x2 + p(3x + 1) = 0 p(3x+1) = -x2 p = -x2/(3x+1) So p can have any value at all. In fact, around x = -1/3, p goes asymptotically to + and - infinity.