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limx->1 (x-1)/(x^3-1). You can factor and solve it that way, but I'm going to show a cooler way to do it: If you've heard of L'Hopital's Rule, then you know that limx->1 (x-1)/(x^3-1)=limx->1 (1/3x^2)=1/3(1)=1/3

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Q: Limit x approaches 1 x minus 1 divided by x cubed minus 1?
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