answersLogoWhite

0

limx->1 (x-1)/(x^3-1). You can factor and solve it that way, but I'm going to show a cooler way to do it: If you've heard of L'Hopital's Rule, then you know that limx->1 (x-1)/(x^3-1)=limx->1 (1/3x^2)=1/3(1)=1/3

User Avatar

Wiki User

11y ago

What else can I help you with?

Related Questions

What is x cubed minus 27 divided by x minus 3?

24


What is the limit as x approaches 1 when 1 minus square root of 2x squared minus 1 divided by x-1?

The answer will depend on any parentheses present in the expression. Until these are given explicitly, it is not possible to answer the question.


What is 356 divided by 21 times 100 minus 36 plus 73 cubed?

390,676.238095


What is the quotient and remainder when 8x cubed minus 24x plus 9 is divided by 2x minus 3?

4x2 + 6x - 3 (with no remainder)


What is negative 4 times 3 minus negative 4 minus negative 10 cubed plus three divided by three?

993


x cubed minus x?

X cubed - X cubed is zero.


How do you factor 64 x cubed minus y cubed?

64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)


What is the limit of sin multiplied by x minus 1 over x squared plus 2 as x approaches infinity?

As X approaches infinity it approaches close as you like to 0. so, sin(-1/2)


What is 2 cubed plus the square root of 25 times 3 minus 4 divided by the square root of 4?

29.5


What is minus 1 cubed?

-1


What is 2 cubed minus 3 squared?

9 minus 8


Is zero divided by zero equal to zero?

Actually 0/0 is undefined because there is no logical way to define it. In ordinary mathematics, you cannot divide by zero.The limit of x/x as x approaches 0 exists and equals 1 so you might be tempted to define 0/0 to be 1.However, the limit of x2/x as x approaches 0 is 0, and the limit of x/x2 as x approaches 0 does not exist .r/0 where r is not 0 is also undefined. It is certainly misleading, if not incorrect to say that r/0 = infinity.If r > 0 then the limit of r/x as x approaches 0 from the right is plus infinity which means the expression increases without bounds. However, the limit as x approaches 0 from the left is minus infinity.