1
the sum of my digits is 6? answer=60
If the sum of its digits add up to 9 then it is divisable by 9
Add the digits together. The sum of the digits of 23 is 5.
No it is not. To check - add all the digits together (in this case 2+6+9=17. If the sum of the digits can be divided exactly by 3, then the number itself will also divide by 3. In this case, 17 (the sum of the digits) does not divide exactly by 3.
By the sum of its digits: 10. By each of its individual digits: 11.
You can tell if the sum of the digits can be divided by 3.
0.1154
That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.
78
1
the sum of my digits is 6? answer=60
Take the question apart, one step at a time. The remainder, when the number is divided by 5, is 4. That means that the ones digit is either 4 or 9. However, you know that both digits are odd, which means it has to be 9. The sum of the digits is 10, so the tens digit has to be 1. Your number is 19.
If the sum of its digits add up to 9 then it is divisable by 9
Add the digits together. The sum of the digits of 23 is 5.
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
19