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0; 27; 36; 45;... there are a bunch... an infinite number of answers actually
No it is not. To check - add all the digits together (in this case 2+6+9=17. If the sum of the digits can be divided exactly by 3, then the number itself will also divide by 3. In this case, 17 (the sum of the digits) does not divide exactly by 3.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
If the sum of its digits add up to 9 then it is divisable by 9
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.
Yes.
You can tell if the sum of the digits can be divided by 3.
0.1154
That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.
A number is divisible by 3 if the sum of its digits is divisible by 3.
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
No it is not. To check - add all the digits together (in this case 2+6+9=17. If the sum of the digits can be divided exactly by 3, then the number itself will also divide by 3. In this case, 17 (the sum of the digits) does not divide exactly by 3.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
If the sum of its digits add up to 9 then it is divisable by 9
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
That number would be 43.
693 can be divided by 3 ==> composite number. This is an easy prime because if you make a sum of all the digits: 6 + 9 + 3 = 18, if you can devide this sum by 3 than you can also divide the original number by 3.