I assume you mean on one of those graphs that has a x and y axis. You need to remember that x ALWAYS goes before y. Think of it like you crawl before you walk. Since it's 3x, that means start at the very senter of the graph. Move to the right 3 spaces. From there, you go up 6 spaces for the y. That should be your spot. This is all just like battleship.
-3
3x y^3
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
-1
3-y6 = -3
-3
3x y^3
Assuming the line is 3x - 2y = 4, the point (1, -1/2) lies in it.
y = 3x+5 is parallel to y = 3x+7
3x + y = 4 y = -3x + 4 (the slope is -3) The line that passes through the point (-3, -2) has a slope of -3, since it is parallel to the line with equation 3x + y = 4 (parallel lines have equal slopes). Using the slpoe -3 and the point (-3, -2) we find the equation of the required line such as (y - -2) = -3(x - -3) y + 2 = -3x - 9 y = -3x -11 3x + y = -11
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
Depending on the domain of x, there are infinitely many points on the line. Select any value for x, calculate y = -2 - 3x. Then the point (x, -2 - 3x) is on the line.
y = 3x - 3
y-6=3x-5 y=3x+1 (0,1)(1,4)(2,7)etc
-1
Assuming the equation of the given line is y = 3x + 4, its gradient is 3.Therefore the gradient of the required line is 3. The line passes through (3, 1) and so its equation is y - 1 = 3*(x - 3) = 3x - 9 So y = 3x - 8
3-y6 = -3