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I assume you mean on one of those graphs that has a x and y axis. You need to remember that x ALWAYS goes before y. Think of it like you crawl before you walk. Since it's 3x, that means start at the very senter of the graph. Move to the right 3 spaces. From there, you go up 6 spaces for the y. That should be your spot. This is all just like battleship.

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Q: Point on the line 3x y6?
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What is the slope of the line 3x-y6?

-3


Square root 9x2 y6?

3x y^3


Which point lies on the line defined by 3x-2y4?

Assuming the line is 3x - 2y = 4, the point (1, -1/2) lies in it.


How you would write the equation of a line given a point on the line and a parallel line?

y = 3x+5 is parallel to y = 3x+7


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3x + y = 4 y = -3x + 4 (the slope is -3) The line that passes through the point (-3, -2) has a slope of -3, since it is parallel to the line with equation 3x + y = 4 (parallel lines have equal slopes). Using the slpoe -3 and the point (-3, -2) we find the equation of the required line such as (y - -2) = -3(x - -3) y + 2 = -3x - 9 y = -3x -11 3x + y = -11


What is the equation of a line that contains the point (21) and is perpendicular to the line y 3x 4?

If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5


Which point lies on the line defined by 2y equals -4-6x?

Depending on the domain of x, there are infinitely many points on the line. Select any value for x, calculate y = -2 - 3x. Then the point (x, -2 - 3x) is on the line.


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What is the written equation of a line in standard form that passes through the point 3 1 and is parallel to the line y 3x plus 4?

Assuming the equation of the given line is y = 3x + 4, its gradient is 3.Therefore the gradient of the required line is 3. The line passes through (3, 1) and so its equation is y - 1 = 3*(x - 3) = 3x - 9 So y = 3x - 8


What is 3-y6?

3-y6 = -3