To determine the displacement of the walker, we can use the Pythagorean theorem. The walker travels 4 km east and 3 km north, forming a right triangle with these two legs. The displacement (d) is the hypotenuse, calculated as ( d = \sqrt{(4^2 + 3^2)} = \sqrt{16 + 9} = \sqrt{25} = 5 ) km. Therefore, the displacement of the walker is 5 km in a direction northeast.
south
Indeed it is.
Draw a vector from his starting point to his ending point.
To find the displacement, we can determine the final position relative to the starting point. The person moves 3 km east, then 3.5 km east (totaling 6.5 km east), and 2 km north. Using the Pythagorean theorem, the displacement is calculated as the hypotenuse of the triangle formed by the eastward and northward distances: ( \sqrt{(6.5^2 + 2^2)} = \sqrt{(42.25 + 4)} = \sqrt{46.25} \approx 6.8 ) km. Thus, the total displacement is approximately 6.8 km at an angle north of east.
To calculate displacement, we determine the net change in position from the starting point. Starting at the origin, you walk 100 m north, then 20 m east, 30 m south, 50 m west, and finally 70 m south. The net movement in the north-south direction is 100 m north - 30 m south - 70 m south = 0 m, and in the east-west direction, it’s 20 m east - 50 m west = -30 m (or 30 m west). Therefore, the displacement is 30 m west.
subtract 1 from 2
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
south
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
Indeed it is.
It's 17.0m North. (20N - 3S)
The displacement of the car is 50 km North. Displacement is a vector quantity that represents the shortest distance and direction from the initial to the final position of an object.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
5 km North
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.
The total displacement is 2km north, as the southward and northward displacements cancel each other out.