To determine the displacement of the walker, we can use the Pythagorean theorem. The walker travels 4 km east and 3 km north, forming a right triangle with these two legs. The displacement (d) is the hypotenuse, calculated as ( d = \sqrt{(4^2 + 3^2)} = \sqrt{16 + 9} = \sqrt{25} = 5 ) km. Therefore, the displacement of the walker is 5 km in a direction northeast.
To determine Mark's total displacement, you can use the Pythagorean theorem. He walked 2 miles east and 1 mile north, forming a right triangle where the legs are 2 miles and 1 mile. The displacement is the hypotenuse, calculated as √(2² + 1²) = √(4 + 1) = √5, which is approximately 2.24 miles in a northeast direction.
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
south
Indeed it is.
To find the total displacement, we need to calculate the net movement in the north-south direction. The child walks 4m south and 5m south, totaling 9m south, and then walks 2m north and 5m north, totaling 7m north. The net displacement is 9m south - 7m north = 2m south. Therefore, the total displacement of the child is 2m south.
subtract 1 from 2
To determine Mark's total displacement, you can use the Pythagorean theorem. He walked 2 miles east and 1 mile north, forming a right triangle where the legs are 2 miles and 1 mile. The displacement is the hypotenuse, calculated as √(2² + 1²) = √(4 + 1) = √5, which is approximately 2.24 miles in a northeast direction.
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
south
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
Indeed it is.
It's 17.0m North. (20N - 3S)
The displacement of the car is 50 km North. Displacement is a vector quantity that represents the shortest distance and direction from the initial to the final position of an object.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
5 km North